201205-延庆一模.pdf

《201205-延庆一模.pdf》由会员分享，可在线阅读，更多相关《201205-延庆一模.pdf（10页珍藏版）》请在得力文库 - 分享文档赚钱的网站上搜索。

1、个人收集整理仅供参考学习1/10 12012 年延庆县初中毕业试卷（一模）数学资料个人收集整理，勿做商业用途一、选择题：（共 8 道小题，每小题4 分，共 32 分）在下列各题的四个备选答案中，只有一个是正确的，请将所选答案在答题卡相应位置涂黑。资料个人收集整理，勿做商业用途1 3 的绝对值是A-3B 3C13D132.截至 2011年底，我国铁路营业里程达到86 000 公里，跃居世界第二位.将 86 000 用科学记数法表示为资料个人收集整理，勿做商业用途A50.8610B386 10C48.6 10D58.6103下列运算中正确的是Aa3a2=a6B （a3）4=a7Ca6 a3=a2D

2、a5+a5=2 a54.一个布袋中有4 个除颜色外其余都相同的小球，其中3 个白球，1 个红球从袋中任意摸出 1 个球是白球的概率是资料个人收集整理，勿做商业用途A43B41C32D315.若右图是某几何体的三视图，则这个几何体是A直棱柱 B球C圆柱 D圆锥6.0312yx，则2()xy的值为A6B 9 C6 D97如右图所示，已知AB CD，EF平分 CEG，180，则 2 的度数为A20 B40 C50 D60考生须知:1.本试卷分试题和答题卡两部分.满分 120 分,考试时间120 分钟.2.答题前，考生务必将自己的学校名称、姓名、班级填写清楚.3.本试卷中的选择题及作图题用2B 铅笔做

3、答,其它题目用黑色或蓝色的签字笔或钢笔做答.4.修改时，选择题及作图用橡皮擦干净，不得使用涂改液。请保持卡面清洁，不要折叠、弄破.5.请按照题号顺序在各题目的答题区域内做答，超出答题区域的答案无效.6.草稿一律不得写在答题卡上，考试结束后,只上交答题卡.1 2 G B D C A F E 个人收集整理仅供参考学习2/10 8将图 1 围成图 2 的正方体，则图1 中的红心“”标志所在的正方形是正方体中的A面 CDHE B面 BCEFC 面 ABFG D面 ADHG 二、填空题（共4 道小题，每小题4 分，共 16 分）9若代数式3x有意义，则实数x的取值范围为_ _ 10.分解因式：24axa

4、=11用配方法把422xxy化为khxay2)(的形式为12将1、2、3、6按右侧方式排列若规定（m,n）表示第m排从左向右第n 个数，则（7,3）所表示的数是；（5，2）与（20，17）表示的两数之积是资料个人收集整理，勿做商业用途三、解答题（共5 道小题，每小题5 分，共 25 分）13（本题满分5 分）计算:01)3()21(60sin22714（本题满分5 分）化简求值：当22310 xx时，求2(2)(5)28xx xx的值.15（本题满分5 分）求不等式组xxxx15234)2(2的整数解16（本题满分5 分）已知：如图，ABCD中，点E是AD的中点，延长CE交BA的延长线于点F1

5、11122663263323第1排第2排第3排第4排第5排文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ

6、10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R

7、1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC1

8、0Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9

9、J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9

10、HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6

11、I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编

12、码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1个人收集整理仅供参考学习3/10 AFDOEBGC求证：AB=AF 17（本题满分5 分）已知 A(n，-2)，B(1，4)是一次函数y=kx+b 的图象和反比例函数 y=xm的图象的两个交点，直线AB与 y 轴交于点 C资料个人收集整理，勿做商业用途 (1)求反比例函数和一次函数的关系式；(2)求AOC的面积；(3)求不等式 kx+b-xm0）。（1）求：点A、点 B 的坐标（含m 的式子表示）；（2）若 OB=4AO，点 D 是线段 OC（不与点O、点 C 重合）上一动点，在线段OD 的右侧作正方形ODEF,

13、连接 CE、BE，设线段OD=t，CEB 的面积为 S，求 S与 t 的函数关系式，并写出自变量t 的取值范围；八、解答题（本题满分7 分）24.如图 1，已知：已知：等边 ABC，点 D 是边 BC 上一点（点 D 不与点 B、点 C 重合），求证：BD+DC AD 下面的证法供你参考：你们是用9 天完成 4800 米长的大坝加固任务的?我们加固600 米后,采用新的加固模式,这样每天加固长度是原来的2 倍通过这段对话,请你求出该地驻军原来每天加固的米数.CA文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y

14、10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J1

15、0W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ

16、10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R

17、1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC1

18、0Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9

19、J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9

20、HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1个人收集整理仅供参考学习5/10 6425510 xyO把ACD绕点 A 瞬时间针旋转60得到ABE，连接 E

21、D，则有ABEACD,DC=EB AD=AE,60DAEADE是等边三角形AD=DE 在DBE中，BD+EB DE 即：BD+DC AD 实践探索：（1）请你仿照上面的思路，探索解决下面的问题：如图 2，点 D 是等腰直角三角形ABC 边上的点（点D 不与 B、C 重合），求证：BD+DC2AD（2）如果点D运动到等腰直角三角形ABC 外或内时，BD、DC 和 AD 之间又存在怎样的数量关系？直接写出结论.资料个人收集整理，勿做商业用途创新应用：（3）已知：如图3，等腰 ABC 中，AB=AC，且 BAC=（为钝角），D 是等腰 ABC 外一点，且BDC+BAC=180o，BD、DC 与 AD

22、 之间存在怎样的数量关系？写出你的猜想，并证明.资料个人收集整理，勿做商业用途九、解答题（本题满分8 分）25.在平面直角坐标系xOy 中，已知二次函数y1=ax2+3x+c 的图像经过原点及点A（1,2），与 x 轴相交于另一点B。（1）求：二次函数y1的解析式及B 点坐标；（2）若将抛物线y1以 x=3 为对称轴向右翻折后，得到一个新的二次函数y2,已知二次函数 y2与 x 轴交于两点，其中右边的交点为C 点.点 P在线段 OC上，从 O点出发向C点运动，过 P点作 x 轴的垂线，交直线AO于 D点，以 PD为边在 PD的右侧作正方形PDEF（当P点运动时，点D、点 E、点 F 也随之运动

23、）；资料个人收集整理，勿做商业用途当点 E在二次函数y1的图像上时，求OP的长。若点 P 从 O点出发向C点做匀速运动，速度为每秒1 个单位长度，同时线段OC上另一个点 Q从 C点出发向O点做匀速运动，速度为每秒2 个单位长度（当 Q点到达 O点时停止运动，P 点也同时停止运动）。过 Q点作 x 轴的垂线，与直线AC交于 G点，以 QG为边在QG的左侧作正方形QGMN（当 Q点运动时，点G、点 M、点 N也随之运动），若 P点运动 t秒时，两个正方形分别有一条边恰好落在同一条直线上（正方形在x 轴上的边除外），求此刻 t 的值。资料个人收集整理，勿做商业用途12012 年延庆县初中毕业试卷参考

24、答案CABD图 2 CDAB图 3 文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9

25、 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W

26、6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档

27、编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5

28、Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E

29、7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8

30、Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J

31、10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1个人收集整理仅供参考学习6/10 一、选择题（共8 个小题，每题4 分，共 32 分）题号1 2 3 4 5 6 7 8 答案B C D A DBCA二、填空题（共 4 个小题，每小题4 分，共 16 分）题号9101112答案x3a（x+2）（x-2）3)1(2xy6；23三、解答题（共5 道小题，13-17 每小题 5 分，共 25 分）13 解：原式12232334 分3325 分14.解：22528xx xx=2244528xxxxx2 分=2234xx3 分2231xx=0 2231xx4 分原式=2234xx=1455 分

32、15.解：由得21x；2 分由得 x 2 3分 此不等式组的解集为221x4 分此不等式组的整数解为0，1 5 分16.证明：四边形ABCD 是平行四边形，ABCD 且 AB=CD F=2,1=D-1分 E 为 AD 中点，AE=ED.-2分在 AEF 和 DEC 中文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC

33、10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P

34、9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9

35、 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W

36、6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档

37、编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5

38、Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E

39、7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1个人收集整理仅供参考学习7/10 21FDAEED，AEF DEC-3分AF=CD.-4 分AB=AF.-5 分17解：（1）将 B（1，4）代入myx中，得 m=4，4yx.-1分将 A（n,-2）代入myx中，得 n=-2.将 A（-2,-2）、B（1，4）代入ykxb，得224kbkb.-2分解得22

40、kb，22yx.-3分（2）当 x=0 时，y=2，OC=2，12222AOCS.-4分（3）2x或01x.-5分四、解答题（共2 道小题，共10 分）18解：过点A 作 AEBC，垂足为E，得矩形ADCE，CE=AD=12.-1分资料个人收集整理，勿做商业用途RtACE中，EAC=60，CE=12，AE=4 3tan60CE.-2分RtABE中，BAE=30，BE=AEtan304.-3分BC=CE+BE=16m.-4分答：旗杆的高度为16m.-5分19.（1）证明：连接OE，-1分AB=BC 且 D 是 BC 中点BD AC BE平分 ABD ABE=DBE 文档编码:CJ10W6I4J1

41、0W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ

42、10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R

43、1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC1

44、0Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9

45、J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9

46、HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6

47、I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1个人收

48、集整理仅供参考学习8/10 OB=OE OBE=OEB OEB=DBE OE BD OE AC AC与 O相切-2分（2）BD=6，sinC=53，BD AC BC=10-3分AB=10 设 O 的半径为r，则 AO=10-r AB=BC C=A sinA=sinC=53AC与 O相切于点E，OE AC sinA=OAOE=rr10=53-4分资料个人收集整理，勿做商业用途r=415 -5分资料个人收集整理，勿做商业用途五、解答题（本题满分6 分）20解：A组的户数是：（105）1=2 1 分调查样本的容量是:（10+2）（1-40%-28%-8%）=50 2分C组的户数是：5040%=20

49、3分并补全直方图（略）4 分估计捐款不少于300 元的户数是：500（28%+%）=180 户 6 分六、解答题（共2 道小题，共9 分）21.解：设原来每天加固x米，根据题意，得1 分926004800600 xx2 分去分母，得 1200+4200=18x（或 18x=5400）解得300 x3 分检验：当300 x时，20 x（或分母不等于0）300 x是原方程的解4 分文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8

50、Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J10W9 HL8Y10P9J5E7 ZC10Y5Z2Y6R1文档编码:CJ10W6I4J