2021年高等数学电子版.pdf

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1、.-.word.zl-第一章极限与连续第一节数列的极限一、数列极限的概念按照某一法则,对于每一个Nn,对应一个确定的实数nx,将这些实数按下标n从小到大排列,得到一个序列,21nxxx称为数列,简记为数列nx,nx称为数列的一般项。例如:,1,43,32,21nn,2,8,4,2n,21,81,41,21n,)1(,1,1,11n,)1(,56,43,34,21,21nnn一般项分别为1nn,n2,n21,1)1(n,nnn 1)1(数列nx可看成自变量取正整数n的函数,即)(nfxn,Nn设数列nnxnn1)1(,来说明数列nx以 1为极限。为 使100111)1(|1|1nnnxnn,只

2、需 要100n,即 从101 项 以 后 各 项 都 满 足1001|1|nx,为使100000111)1(|1|1nnnxnn,只需要100000n,即从 100001项以后各项都满足1000001|1|nx,为使nnnxnn11)1(|1|1(是任意给定的小正数),只需要1n,即当1n以后,各项都满足|1|nx。令1N,当Nn时,1n,因此有|1|nx,即任意给定小正数,总存在正整数1N,当Nn时的一切nx都满足|1|nx,则定义:设nx为一数列,如果存在常数a,对于任意给定的正数(不论它多么小),总存在正整数N,使得当Nn时的一切nx都满足不等式|axn则说常数a是数列nx的极限,或者说

3、数列nx收敛于a,记为axnnlim或axn)(n如果不存在这样的常数a,则说数列nx没有极限,或者说数列nx发散。|精.|品.|可.|编.|辑.|学.|习.|资.|料.*|*|*|*|欢.|迎.|下.|载.第 1 页,共 17 页.-.word.zl-数列nx以a为极限的几何意义:任意给定的正数,总存在正整数N,当Nn时的一切nx,有|axn即axan或),(aaxn也就是当Nn的一切nx都落在a的邻域),(aU,在),(aU的外边至多有N项(图)1xNxa1Nxa2Nxa例 1 证明数列,1,43,32,21nn的极限为1。证明:分析:为使11|nnaxn,只需要11n,或11n,即11n

4、证明:任意给定小正数,取11N,当Nn时的一切nx满足1111|1|nnnxn因此,11limnnn例 2 已知2)1()1(nxnn,证明数列nx的极限是0。分析:为使0)1()1(|2naxnn,只需要2)1(1n,由于11)1(1)1(122nnn,故11n时,即11n,或11n时2)1(1n。证明:任意给定小正数,取 11N,当Nn时的一切nx满足11)1(10)1()1(|0|2nnnxnn因此,0)1()1(lim2nnn例 3 设1|q,证明等比数列,112nqqq的极限是0。证明:任给0(设0),由于11|0|0|nnnqqx为使|0|nx,只需11|0|nnqq,解得ln|l

5、n)1(qn,或|lnln1qn。故取|lnln1qN,当Nn时,有11|0|0|nnnqqx因此,0lim1nnq。二、收敛数列的性质|精.|品.|可.|编.|辑.|学.|习.|资.|料.*|*|*|*|欢.|迎.|下.|载.第 2 页,共 17 页文档编码:CL4Q8N7W10M10 HP4H8N5K9L3 ZU1V7Q4S1U8文档编码:CL4Q8N7W10M10 HP4H8N5K9L3 ZU1V7Q4S1U8文档编码:CL4Q8N7W10M10 HP4H8N5K9L3 ZU1V7Q4S1U8文档编码:CL4Q8N7W10M10 HP4H8N5K9L3 ZU1V7Q4S1U8文档编码:C

6、L4Q8N7W10M10 HP4H8N5K9L3 ZU1V7Q4S1U8文档编码:CL4Q8N7W10M10 HP4H8N5K9L3 ZU1V7Q4S1U8文档编码:CL4Q8N7W10M10 HP4H8N5K9L3 ZU1V7Q4S1U8文档编码:CL4Q8N7W10M10 HP4H8N5K9L3 ZU1V7Q4S1U8文档编码:CL4Q8N7W10M10 HP4H8N5K9L3 ZU1V7Q4S1U8文档编码:CL4Q8N7W10M10 HP4H8N5K9L3 ZU1V7Q4S1U8文档编码:CL4Q8N7W10M10 HP4H8N5K9L3 ZU1V7Q4S1U8文档编码:CL4Q8N7

7、W10M10 HP4H8N5K9L3 ZU1V7Q4S1U8文档编码:CL4Q8N7W10M10 HP4H8N5K9L3 ZU1V7Q4S1U8文档编码:CL4Q8N7W10M10 HP4H8N5K9L3 ZU1V7Q4S1U8文档编码:CL4Q8N7W10M10 HP4H8N5K9L3 ZU1V7Q4S1U8文档编码:CL4Q8N7W10M10 HP4H8N5K9L3 ZU1V7Q4S1U8文档编码:CL4Q8N7W10M10 HP4H8N5K9L3 ZU1V7Q4S1U8文档编码:CL4Q8N7W10M10 HP4H8N5K9L3 ZU1V7Q4S1U8文档编码:CL4Q8N7W10M10

8、 HP4H8N5K9L3 ZU1V7Q4S1U8文档编码:CL4Q8N7W10M10 HP4H8N5K9L3 ZU1V7Q4S1U8文档编码:CL4Q8N7W10M10 HP4H8N5K9L3 ZU1V7Q4S1U8文档编码:CL4Q8N7W10M10 HP4H8N5K9L3 ZU1V7Q4S1U8文档编码:CL4Q8N7W10M10 HP4H8N5K9L3 ZU1V7Q4S1U8文档编码:CL4Q8N7W10M10 HP4H8N5K9L3 ZU1V7Q4S1U8文档编码:CL4Q8N7W10M10 HP4H8N5K9L3 ZU1V7Q4S1U8文档编码:CL4Q8N7W10M10 HP4H8

9、N5K9L3 ZU1V7Q4S1U8文档编码:CL4Q8N7W10M10 HP4H8N5K9L3 ZU1V7Q4S1U8文档编码:CL4Q8N7W10M10 HP4H8N5K9L3 ZU1V7Q4S1U8文档编码:CL4Q8N7W10M10 HP4H8N5K9L3 ZU1V7Q4S1U8文档编码:CL4Q8N7W10M10 HP4H8N5K9L3 ZU1V7Q4S1U8文档编码:CL4Q8N7W10M10 HP4H8N5K9L3 ZU1V7Q4S1U8文档编码:CL4Q8N7W10M10 HP4H8N5K9L3 ZU1V7Q4S1U8文档编码:CL4Q8N7W10M10 HP4H8N5K9L3

10、 ZU1V7Q4S1U8文档编码:CL4Q8N7W10M10 HP4H8N5K9L3 ZU1V7Q4S1U8文档编码:CL4Q8N7W10M10 HP4H8N5K9L3 ZU1V7Q4S1U8文档编码:CL4Q8N7W10M10 HP4H8N5K9L3 ZU1V7Q4S1U8文档编码:CL4Q8N7W10M10 HP4H8N5K9L3 ZU1V7Q4S1U8文档编码:CL4Q8N7W10M10 HP4H8N5K9L3 ZU1V7Q4S1U8文档编码:CL4Q8N7W10M10 HP4H8N5K9L3 ZU1V7Q4S1U8文档编码:CL4Q8N7W10M10 HP4H8N5K9L3 ZU1V7

11、Q4S1U8文档编码:CL4Q8N7W10M10 HP4H8N5K9L3 ZU1V7Q4S1U8文档编码:CL4Q8N7W10M10 HP4H8N5K9L3 ZU1V7Q4S1U8文档编码:CL4Q8N7W10M10 HP4H8N5K9L3 ZU1V7Q4S1U8文档编码:CL4Q8N7W10M10 HP4H8N5K9L3 ZU1V7Q4S1U8文档编码:CL4Q8N7W10M10 HP4H8N5K9L3 ZU1V7Q4S1U8文档编码:CL4Q8N7W10M10 HP4H8N5K9L3 ZU1V7Q4S1U8文档编码:CL4Q8N7W10M10 HP4H8N5K9L3 ZU1V7Q4S1U8

12、文档编码:CL4Q8N7W10M10 HP4H8N5K9L3 ZU1V7Q4S1U8.-.word.zl-定理 1(极限的唯一性)如果数列nx收敛,则它的极限是唯一的。证明:反证法:如果axn,bxn,不妨设ba。取2ab。由于axn,存在1N,当1Nn时,2|abaxn;又由于bxn,存在2N,当2Nn时,2|abbxn。取,max21NNN,则当Nn时,2|abaxn,2|abbxn,由2|abaxn得2baxn,由2|abbxn得2baxn,矛盾,故必须ba。例 4 证明数列1)1(nnx(,2,1n)是发散的。对于数列nx,如果存在正数M,使得对于一切nx,有Mxn|,则说数列nx是有

13、界的;否则,则说数列nx是无界的。定理 2(收敛数列的有界性)如果数列nx有极限,则数列nx一定有界。证明:注意到|aaxaaxxnnn,可证明定理2。定理 3(收敛数列的保号性)如果axnnlim,且0a(或0a),则存在正整数N,当Nn时的一切nx,有0nx(或0nx)。证明:取2a即可证明定理。推论如果数列nx从某项起有0nx(或0nx),且axnnlim,则0a(或0a)。对于数列nx,从中抽取1nx,2nx,knx,称为数列nx的一个子数列。定理 4 如果数列nx收敛于a,则数列nx的任何子数列都收敛,且收敛于a。第二节函数的极限一、函数极限的定义1自变量趋向于无穷大时函数的极限数

14、列 是 特 殊的 函 数,如1)(nnnfxn,,2,1n,且n时,1nx,考 虑函 数1)(xxxfy,是否有x时,1)(xf?任 意 给 定 小 正 数,为 使|11|1)(|xxxf,只 要|11|x,即1|1|x。由 于1|1|xx,即11|x即可。任给0,存在正数11X,当Xx|时,对应的函数值)(xf满足|11|1)(|xxxf即当x时,)(xf以 1为极限。定义 1 设函数)(xf当|x大于某一正数时有定义。如果存在常数A,对于任意给定的正数(不论|精.|品.|可.|编.|辑.|学.|习.|资.|料.*|*|*|*|欢.|迎.|下.|载.第 3 页,共 17 页文档编码:CB5S

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16、0T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6

17、R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB

18、5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6

19、S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5

20、W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:

21、CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9.-.word.zl-它多么小),总存在正数X,使得x满足不等式Xx|时,对应函数值)(xf满足|)(|Axf则说常数A为函数)(xf当x时的极限,记为Axfx)(lim或Axf)((当x)Axfx)(lim:0,0X,当Xx|时,|)(|Axf。例 1 证明03limxx。分析:

22、为使|03|x,只要|3|x,即|3x,或3|x。证明:0,3X,当Xx|时,|3|03|xx,因此03limxx。Axfx)(lim的几何解释:0,0X,当Xx|时,|)(|Axf即Axf)(或AxfA)(如图所示:如果0,0X,当Xx时,|)(|Axf,则说x时,Axf)(,记为Axfx)(lim;如果0,0X,当Xx时,|)(|Axf,则说x时,Axf)(,记为Axfx)(lim显然,Axfx)(limAxfx)(lim,Axfx)(lim例如:xxxf|)(,有1)(limxfx,1)(limxfx。2自变量趋向于有限值时函数的极限例 1,12)(xxf,2x时,5)(xf;例 2:1

23、1)(2xxxf,定义域为1x,但1x时,2)(xf;任 意 给 定 小 正 数,为 使|42|512|)(|xxAxf,只 要|2|2 x,即2|2|x即可。任意给定小正数,为使|21)1)(1(|211|)(|2xxxxxAxf只要|1|x,即|1|0 x即可。定义 2 设函数)(xf在点0 x的某一去心邻域内有定义。如果存在常数A,对于任意给定的正数(不论它多么小),总存在正数,使得x满足不等式|00 xx时,对应函数值)(xf满足|精.|品.|可.|编.|辑.|学.|习.|资.|料.*|*|*|*|欢.|迎.|下.|载.第 4 页,共 17 页文档编码:CB5S5P2R4G3 HU6S

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25、6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:C

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27、6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ

28、5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码

29、:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3

30、HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9.-.word.zl-|)(|Axf则说常数A为函数)(xf当0 xx时的极限,记为Axfxx)(lim0或Axf)((当0 xx)Axfxx)(lim0:0,0,当|00 xx时,|)(|Axf。例 2 证明8)13(lim3xx。分析:为使|93|8)13(|xx,只要|3|3 x,即3|3|x。证明

31、:0,取3,当|3|0 x时,对应函数值满足|3|3|8)13(|8)(|xxxf因此,8)13(lim3xx。Axfxx)(lim0的几何解释:0,0,当|00 xx时,|)(|Axf即Axf)(或AxfA)(即),(00 xUx时,),()(AUxf如图所示:如果0,0,当0 xx时,|)(|Axf,则说x从0 x的右侧趋向于0 x(记为0 xx)时,Axf)(,记为Axfxx)(lim0,或Axf)(0;如果0,0,当xx0时,|)(|Axf,则说x从0 x的左侧趋向于0 x(记为0 xx)时,Axf)(,记为Axfxx)(lim0,或Axf)(0;显然,Axfxx)(lim0Axfxx

32、)(lim0,Axfxx)(lim0例 3 设函数0,10,00,1)(xxxxxxf当0 x时,)(xf的极限不存在。例 4 证明ccxx0lim例 5 证明00limxxxx例 6 证明424lim22xxx例 7 证明0sinlimxxx二、函数极限的性质定理 1(函数极限的唯一性)如果)(lim0 xfxx存在,则极限是唯一的。定理 2(函数极限的局部有界性)如果Axfxx)(lim0,则存在正数M和,使得当|00 xx|精.|品.|可.|编.|辑.|学.|习.|资.|料.*|*|*|*|欢.|迎.|下.|载.第 5 页,共 17 页文档编码:CB5S5P2R4G3 HU6S10T1U

33、2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5

34、J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P

35、2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T

36、1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2

37、D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S

38、5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S1

39、0T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9.-.word.zl-时,有Mxf|)(|。证明:|)(|)(|)(|AAAxfAAxfxf定理 3(函数极限的局部保号性)如果Axfxx)(lim0,且0A(或0A),则存在常数0,使得当|00 xx时,有0)(xf(或0)(xf)。推论如果在0 x的某去心邻域),(00 xU,0)(xf(或0)(xf),且Ax

40、fxx)(lim0,则0A(或0A)。定理 4(函数极限与数列极限的关系)如果极限Axfxx)(lim0,nx为函数)(xf定义域内一收敛0 x的数列,且0 xxn(Nn),则对应的函数值数列)(nxf也收敛,且Axfxfxxnn)(lim)(lim0。证明:由于Axfxx)(lim0,则0,0,当|00 xx时,有|)(|Axf;又由于0limxxnn,故对于上面的0,N,当Nn时,有|0 xxn,当然有|00 xxn;因此,0,N,当Nn时,有|00 xxn,故|)(|Axfn,即Axfnn)(lim。第三节无穷小与无穷大一、无穷小定义1 如果函数)(xf当0 xx(或x)时的极限为零,则

41、函数)(xf称为当0 xx(或x)时的无穷小。例如:0)1(lim1xn,因此)1(x为1x时的无穷小;01limxn,因此x1为x时的无穷小。)(xf为0 xx时 的 无 穷 小0)(lim0 xfxn0,0,当|00 xx时,|)(|xf;)(xf为x时的无穷小0)(limxfn0,0X,当Xx|时,|)(|xf;定理 1 在自变量的同一变化过程0 xx(或x)中,函数)(xf以A为极限的充分必要条件是Axf)(,其中是无穷小。证明:必要性:设Axfxn)(lim0,则0,0,当|00 xx时,|)(|Axf。令Axf)(,则是0 xx时的无穷小,且Axf)(。充分性:设Axf)(,其中A

42、为常数,是0 xx时的无穷小。于是,0,0,当|00 xx时,|,即|)(|Axf,因 此,A为)(xf当0 xx时 的 极 限,或Axfxn)(lim0。二、无穷大如果当0 xx(或x)时,对应的函数值的绝对值|)(|xf无限增大,则称函数)(xf为0 xx(或x)时的无穷大。定义 2 设函数)(xf在0 x的某一去心邻域内有定义(或|x大于某一正数时有定义)如果对于任意给定的正数M(不论它多么大),总存在正数(或正数X),当x满足|00 xx(或Xx|)时,|精.|品.|可.|编.|辑.|学.|习.|资.|料.*|*|*|*|欢.|迎.|下.|载.第 6 页,共 17 页文档编码:CB5S

43、5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S1

44、0T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6

45、R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB

46、5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6

47、S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5

48、W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:

49、CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9文档编码:CB5S5P2R4G3 HU6S10T1U2Y4 ZJ5W6R2D5J9.-.word.zl-对应函数值)(xf满足Mxf|)(|则说函数)(xf为0 xx(或x)时的无穷大。如果函数)(xf为0 xx(或x)时的无穷大,也可记为)(lim0 xfxn(或)(limxfn)例如:11x为1x时的无穷大;12x为x时的无穷大。)(lim0 xfxn:0M

50、,0,当|00 xx时,Mxf)(;)(limxfn:0M,0X,当Xx|时,Mxf)(。如果)(lim0 xfxn,则直线0 xx是函数)(xfy的图形的铅直渐近线;如果Axfn)(lim,则直线Ay是函数)(xfy的图形的水平渐近线。定理 2 在自变量的同一变化过程中,如果)(xf为无穷大,则)(1xf为无穷小;反之,如果)(xf为无穷小,且0)(xf,则)(1xf为无穷大。第四节极限运算法则定理 1 有限个无穷小的和也是无穷小。证明:以两个无穷小的和为例:设及是0 xx时的两个无穷小,令。由于是0 xx时无穷小:0,01,当10|0 xx时,2|;又由于是0 xx时无穷小:对于0,02,

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