2015年浙江省高考数学试卷(文科)解析.pdf

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1、第1页共 20页2015年浙江省高考数学试卷文科一、选择题本大题共8 小题，每题5 分，共 40 分。在每题给出的四个选项中，只有一项是符合题目要求的1 5 分 2015?浙江已知集合P=x|x22x 3，Q=x|2 x 4，则 P Q=A3，4B2，3C 1，2D1，32 5 分 2015?浙江某几何体的三视图如下图单位：cm，则该几何体的体积是A8cm3B12cm3CD3 5 分 2015?浙江设a，b 是实数，则“a+b 0”是“ab 0”的A充分不必要条件B必 要不充分条件C 充分必要条件D既 不充分也不必要条件4 5 分 2015?浙江设 ，是两个不同的平面，l，m 是两条不同的直线

2、，且 l?，m?，A假设 l，则 B假设 ，则 l m C假设 l，则 D假设 ，则 lm 5 5分 2015?浙江函数fx=xcosx x 且 x 0的图象可能为ABCD6 5分 2015?浙江有三个房间需要粉刷，粉刷方案要求：每个房间只用一种颜色，且三个房间颜色各不相同已知三个房间的粉刷面积单位：m2分别为x，y，z，且 x y第2页共 20页z，三种颜色涂料的粉刷费用单位：元/m2分别为a，b，c，且 abc在不同的方案中，最低的总费用单位：元是Aax+by+cz Baz+by+cx Cay+bz+cx Day+bx+cz 7 5 分 2015?浙江如图，斜线段AB 与平面 所成的角为6

3、0，B 为斜足，平面上的动点 P满足 PAB=30，则点 P 的轨迹是A直线B抛物线C椭圆D双曲线的一支8 5 分 2015?浙江设实数a，b，t 满足|a+1|=|sinb|=t A假设 t 确定，则b2唯一确定B假 设 t 确定，则 a2+2a 唯一确定C假设 t 确定，则sin 唯一确定D假 设 t 确定，则 a2+a 唯一确定二、填空题本大题共7 小题，多空题每题6 分，单空题每题4 分，共 36 分9 6 分 2015?浙江计算：log2=，2=10 6 分 2015?浙江 已知 an是等差数列，公差 d 不为零，假设 a2，a3，a7成等比数列，且 2a1+a2=1，则 a1=，d

4、=11 6 分 2015?浙江函数fx=sin2x+sinxcosx+1 的最小正周期是，最小值是12 6 分 2015?浙江已知函数f x=，则 f f 2 =，fx的最小值是13 4 分 2015?浙江已知1，2是平面向量，且1?2=，假设平衡向量满足?1=?=1，则|=14 4 分 2015?浙江已知实数x，y 满足 x2+y2 1，则|2x+y4|+|6 x3y|的最大值是文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10

5、P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5

6、 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5

7、S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3

8、文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:C

9、C2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8

10、E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5

11、HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3第3页共 20页15 4 分 2015?浙江椭圆+=1 ab0的右焦点Fc，0关于直线y=x 的对称点 Q 在椭圆上，则椭圆的离心率是三、解答题：本大题共5 小题，共74 分。解答应写出文字说明、证明过程或演算步骤。16 14 分 2015?浙江在 ABC 中，内角 A，B，C 所对的边分别为a，b，c，已知 tan+A=2 求的值；假设 B=，a=3，求 ABC 的面积17 15

12、 分 2015?浙江已知数列an和 bn 满足 a1=2，b1=1，an+1=2ann N*，b1+b2+b3+bn=bn+11n N*求 an与 bn；记数列 anbn的前 n 项和为 Tn，求 Tn1815 分 2015?浙江如图，在三棱柱ABC A1B1C1中，BAC=90 ，AB=AC=2，A1A=4，A1在底面 ABC 的射影为 BC 的中点，D 是 B1C1的中点 证明：A1D平面 A1BC；求直线 A1B 和平面 BB1C1C 所成的角的正弦值19 15 分 2015?浙江如图，已知抛物线C1：y=x2，圆 C2：x2+y12=1，过点 Pt，0 t0作不过原点O 的直线 PA，

13、PB 分别与抛物线C1和圆 C2相切，A，B 为切点 求点 A，B 的坐标；求 PAB 的面积注：直线与抛物线有且只有一个公共点，且与抛物线的对称轴不平行，则称该直线与抛物线相切，称该公共点为切点文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5

14、D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2

15、J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码

16、:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2

17、R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y

18、5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I

19、10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1

20、Z5 ZH5D5S5J2J3第4页共 20页20 15 分 2015?浙江设函数fx=x2+ax+b a，b R 当 b=+1 时，求函数fx在 1，1上的最小值ga的表达式 已知函数fx在 1，1上存在零点，0 b2a 1，求 b 的取值范围文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2

21、R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y

22、5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I

23、10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1

24、Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5

25、D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2

26、J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码

27、:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3第5页共 20页2015 年浙江省高考数学试卷文科参考答案与试题解析一、选择题本大题共8 小题，每题5 分，共 40 分。在每题给出的四个选项中，只有一项是符合题目要求的1 5 分 2015?浙江已知集合P=x|x22x 3，Q=x|2 x 4，则 P Q=A3，4B2，3C 1，2D1，3考点：交集及其运算专题：集合分析：求出集合 P，然后求解交集即可解答：解：集合 P=x|x2 2x 3=x|x 1 或 x 3，Q=x|2 x4，则 PQ=x|3 x4=3，4 故选：A点评：此题考查二次不等式的解法，集合的交集的求

28、法，考查计算能力2 5 分 2015?浙江某几何体的三视图如下图单位：cm，则该几何体的体积是A8cm3B12cm3CD考点：由三视图求面积、体积专题：空间位置关系与距离分析：判断几何体的形状，利用三视图的数据，求几何体的体积即可解答：解：由三视图可知几何体是下部为棱长为2 的正方体，上部是底面为边长2 的正方形奥为 2 的正四棱锥，所求几何体的体积为：23+2 2 2=故选：C文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P

29、3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5

30、ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S

31、5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文

32、档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC

33、2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E

34、10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 H

35、Y1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3第6页共 20页点评：此题考查三视图与直观图的关系的判断，几何体的体积的求法，考查计算能力3 5 分 2015?浙江设a，b 是实数，则“a+b 0”是“ab 0”的A充分不必要条件B必 要不充分条件C 充分必要条件D既 不充分也不必要条件考点：必要条件、充分条件与充要条件的判断专题：简易逻辑分析：利用特例集合充要条件的判断方法，判断正确选项即可解答：解：a，b 是实数，如果a=1，

36、b=2 则“a+b0”，则“ab 0”不成立如果 a=1，b=2，ab0，但是 a+b0 不成立，所以设 a，b 是实数，则“a+b0”是“ab0”的既不充分也不必要条件故选：D点评：此题考查充要条件的判断与应用，基本知识的考查4 5 分 2015?浙江设 ，是两个不同的平面，l，m 是两条不同的直线，且 l?，m?，A假设 l，则 B假设 ，则 l m C假设 l，则 D假设 ，则 lm 考点：空间中直线与平面之间的位置关系专题：综合题；空间位置关系与距离分析：A 根据线面垂直的判定定理得出A 正确；B 根据面面垂直的性质判断B 错误；C 根据面面平行的判断定理得出C 错误；D 根据面面平行

37、的性质判断D 错误解答：解：对于 A，l，且 l?，根据线面垂直的判定定理，得 ，A 正确；对于 B，当 ，l?，m?时，l 与 m 可能平行，也可能垂直，B 错误；对于 C，当 l，且 l?时，与 可能平行，也可能相交，C 错误；对于 D，当 ，且 l?，m?时，l 与 m 可能平行，也可能异面，D 错误故选：A点评：此题考查了空间中的平行与垂直关系的应用问题，也考查了数学符号语言的应用问题，是基础题目5 5分 2015?浙江函数fx=xcosx x 且 x 0的图象可能为ABCD考点：函数的图象专题：函数的性质及应用文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S

38、5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文

39、档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC

40、2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E

41、10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 H

42、Y1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P

43、3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5

44、ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3第7页共 20页分析：由条件可得函数fx为奇函数，故它的图象关于原点对称；再根据在0，1上，fx 0，结合所给的选项，得出结论解答：解：对于函数f x=xcosx x 且 x 0，由于它的定义域关于原点对称，且满足 f x=xcosx=fx，

45、故函数fx为奇函数，故它的图象关于原点对称故排除 A、B再根据在 0，1上，x，cosx0，f x=xcosx0，故排除 C，故选：D点评：此题主要考查函数的奇偶性的判断，奇函数的图象特征，函数的定义域和值域，属于中档题6 5分 2015?浙江有三个房间需要粉刷，粉刷方案要求：每个房间只用一种颜色，且三个房间颜色各不相同已知三个房间的粉刷面积单位：m2分别为x，y，z，且 x yz，三种颜色涂料的粉刷费用单位：元/m2分别为a，b，c，且 abc在不同的方案中，最低的总费用单位：元是Aax+by+cz Baz+by+cx Cay+bz+cx Day+bx+cz 考点：函数的最值及其几何意义专题

46、：函数的性质及应用分析：作差法逐个选项比较大小可得解答：解：xyz 且 a bc，ax+by+cz az+by+cx=axz+cz x=xz ac 0，ax+by+czaz+by+cx；同理 ay+bz+cx ay+bx+cz=bzx+cx z=zx bc 0，ay+bz+cxay+bx+cz；同理 az+by+cx ay+bz+cx=azy+by z=zy ab 0，az+by+cxay+bz+cx，最低费用为az+by+cx 故选：B 点评：此题考查函数的最值，涉及作差法比较不等式的大小，属中档题7 5 分 2015?浙江如图，斜线段AB 与平面 所成的角为60，B 为斜足，平面上的动点

47、P满足 PAB=30，则点 P 的轨迹是文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1

48、Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5

49、D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2

50、J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码:CC2L2R8E10Y5 HY1I10P3N1Z5 ZH5D5S5J2J3文档编码