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1、2019 年山东省滨州市中考数学试卷(A 卷)一、选择题:本大题共12 个小题,在每小题的四个选项中只有一个是正确的,请把正确的选项选出来,用2B 铅笔把答题卡上对应题目的答案标号涂黑。每小题涂对得3 分,满分36 分。1(3 分)下列各数中,负数是()A(2)B|2|C(2)2D(2)02(3 分)下列计算正确的是()Ax2+x3x5Bx2?x3x6Cx3x2xD(2x2)36x63(3 分)如图,AB CD,FGB 154,FG 平分 EFD,则 AEF 的度数等于()A26B52C54D774(3 分)如图,一个几何体由5 个大小相同、棱长为1 的小正方体搭成,下列说法正确的是()A主视
2、图的面积为4B左视图的面积为4C俯视图的面积为3D三种视图的面积都是45(3 分)在平面直角坐标系中,将点A(1,2)向上平移3 个单位长度,再向左平移2个单位长度,得到点B,则点 B 的坐标是()A(1,1)B(3,1)C(4,4)D(4,0)6(3 分)如图,AB 为O 的直径,C,D 为O 上两点,若 BCD40,则 ABD 的大小为()A60B50C40D207(3 分)若 8xmy 与 6x3yn的和是单项式,则(m+n)3的平方根为()A4B8C 4D 88(3 分)用配方法解一元二次方程x24x+10 时,下列变形正确的是()A(x2)21B(x2)25C(x+2)23D(x2)
3、239(3 分)已知点P(a3,2a)关于原点对称的点在第四象限,则a 的取值范围在数轴上表示正确的是()ABCD10(3 分)满足下列条件时,ABC 不是直角三角形的为()AAB,BC4,AC5BAB:BC:AC3:4:5C A:B:C3:4:5D|cosA|+(tanB)2011(3 分)如图,在 OAB 和 OCD 中,OAOB,OC OD,OAOC,AOB COD40,连接 AC,BD 交于点 M,连接 OM下列结论:ACBD;AMB 40;OM 平分 BOC;MO 平分 BMC其中正确的个数为()A4B3C2D112(3 分)如图,在平面直角坐标系中,菱形OABC 的边 OA 在 x
4、 轴的正半轴上,反比例函数 y(x0)的图象经过对角线OB 的中点D 和顶点C若菱形OABC 的面积为12,则 k 的值为()文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7
5、HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E
6、8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文
7、档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10
8、B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H1
9、0 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O
10、9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W
11、7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10A6B5C4D3二、填空题:本大题共8 个小题,每小题5 分,满分40 分。13(5 分)计算:()2|2|+14(5 分)方程+1的解是15(5 分)若一组数据4,x,5,y,7,9的平均数为6,众数为 5,则这组数据的方差为16(5 分)在平面直角坐标系中,ABO 三个顶点的坐标分别为A(2,4),B(4,0),O(0,0)以原点 O 为位似中心,把这个三角形缩小为原来的,得到 CDO,则点 A的对应点C 的坐标是17(5 分)若正六边形的内
12、切圆半径为2,则其外接圆半径为18(5 分)如图,直线ykx+b(k0)经过点 A(3,1),当 kx+bx 时,x 的取值范围为19(5 分)如图,?ABCD 的对角线AC,BD 交于点 O,CE 平分 BCD 交 AB 于点 E,交BD 于点F,且 ABC60,AB2BC,连接OE下列结论:EOAC;SAOD4SOCF;AC:BD:7;FB2OF?DF 其中正确的结论有(填写所有正确结论的序号)20(5 分)观察下列一组数:a1,a2,a3,a4,a5,文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10
13、L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7
14、HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E
15、8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文
16、档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10
17、B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H1
18、0 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O
19、9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10它们是按一定规律排列的,请利用其中规律,写出第 n 个数 an(用含 n 的式子表示)三、解答题:本大题共6 个小
20、题,满分74 分。解答时请写出必要的演推过程。21(10 分)先化简,再求值:(),其中x 是不等式组的整数解22(12 分)有甲、乙两种客车,2 辆甲种客车与3 辆乙种客车的总载客量为180 人,1 辆甲种客车与2 辆乙种客车的总载客量为105 人(1)请问 1 辆甲种客车与1 辆乙种客车的载客量分别为多少人?(2)某学校组织240 名师生集体外出活动,拟租用甲、乙两种客车共6 辆,一次将全部师生送到指定地点若每辆甲种客车的租金为400 元,每辆乙种客车的租金为280 元,请给出最节省费用的租车方案,并求出最低费用23(12 分)某体育老师统计了七年级甲、乙两个班女生的身高,并绘制了以下不完
21、整的统计图请根据图中信息,解决下列问题:(1)两个班共有女生多少人?(2)将频数分布直方图补充完整;(3)求扇形统计图中E 部分所对应的扇形圆心角度数;(4)身高在 170 x175(cm)的 5 人中,甲班有3 人,乙班有2 人,现从中随机抽取两人补充到学校国旗队请用列表法或画树状图法,求这两人来自同一班级的概率24(13 分)如图,矩形ABCD 中,点 E 在边 CD 上,将 BCE 沿 BE 折叠,点C 落在 AD边上的点F 处,过点F 作 FG CD 交 BE 于点 G,连接 CG(1)求证:四边形CEFG 是菱形;文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L
22、10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7
23、H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG
24、5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R
25、3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编
26、码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2
27、J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10
28、ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10(2)若 AB6,AD10,求四边形CEFG
29、的面积25(13 分)如图,在ABC 中,ABAC,以 AB 为直径的 O 分别与 BC,AC 交于点 D,E,过点 D 作 DFAC,垂足为点F(1)求证:直线DF 是 O 的切线;(2)求证:BC24CF?AC;(3)若 O 的半径为4,CDF15,求阴影部分的面积26(14 分)如图 ,抛物线yx2+x+4 与 y 轴交于点A,与 x 轴交于点 B,C,将直线 AB 绕点 A 逆时针旋转90,所得直线与x 轴交于点D(1)求直线 AD 的函数解析式;(2)如图 ,若点 P 是直线 AD 上方抛物线上的一个动点 当点 P 到直线 AD 的距离最大时,求点P 的坐标和最大距离;当点 P 到直
30、线 AD 的距离为时,求 sinP AD 的值文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W
31、7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:
32、CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6
33、R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM
34、9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10
35、L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7
36、HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E
37、8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R102019 年山东省滨州市中考数学试卷(A 卷)参考答案与试题解析一、选择题:本大题共12 个小题,在每小题的四个选项中只有一个是正确的,请把正确的选项选出来,用2B 铅笔把答题卡上对应题目的答案标号涂黑。每小题涂对得3 分,满分36 分。1(3 分)下列各数中,负数是()A(2)B|2|C(2)2D(2)0【分析】直接利用绝对值以及零指数幂的性质、相反数的性质分别化简得出答案【解答】解:A、(2)2,故此选项错误;B、|2|2,故此选项正确;C、(2)24,故此选项错误;D、(2)01,故此选项错误;故选:B【点评】此题主要
38、考查了绝对值以及零指数幂的性质、相反数的性质,正确化简各数是解题关键2(3 分)下列计算正确的是()Ax2+x3x5Bx2?x3x6Cx3x2xD(2x2)36x6【分析】分别利用合并同类项法则以及同底数幂的除法运算法则和积的乘方运算法则等知识分别化简得出即可【解答】解:A、x2+x3不能合并,错误;B、x2?x3x5,错误;C、x3x2x,正确;D、(2x2)38x6,错误;故选:C【点评】此题主要考查了合并同类项法则以及同底数幂的除法运算法则和积的乘方运算法则等知识,正确掌握运算法则是解题关键3(3 分)如图,AB CD,FGB 154,FG 平分 EFD,则 AEF 的度数等于()文档编
39、码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2
40、J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10
41、ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I
42、10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L
43、7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV
44、1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R1
45、0文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L
46、10B2J6R10A26B52C54D77【分析】先根据平行线的性质,得到GFD 的度数,再根据角平分线的定义求出EFD的度数,再由平行线的性质即可得出结论【解答】解:ABCD,FGB+GFD 180,GFD 180 FGB26,FG 平分 EFD,EFD2GFD 52,ABCD,AEF EFD 52故选:B【点评】本题考查的是平行线的性质,用到的知识点为;两直线平行,内错角相等;两直线平行,同旁内角互补4(3 分)如图,一个几何体由5 个大小相同、棱长为1 的小正方体搭成,下列说法正确的是()A主视图的面积为4B左视图的面积为4C俯视图的面积为3D三种视图的面积都是4【分析】根据该几何体的三
47、视图可逐一判断【解答】解:A主视图的面积为4,此选项正确;B左视图的面积为3,此选项错误;C俯视图的面积为4,此选项错误;D由以上选项知此选项错误;故选:A文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档
48、编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B
49、2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10
50、 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9I10L7H10 ZM9L10B2J6R10文档编码:CV1E8R3W7L7 HG5O9