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1、 c(OH B.1.0X10 6 mol L 112 1D.1.0X10 mol LH2SO42LH+,B.1 x 108 mol/LD.1 X 101 mol/L500c(SO42):c(H+)A 1:1 B 1:2 C 1:10 D 10:1 4.HYpH=3.0,pHA.3.0 3.3 B.3.3 3.5 C.3.54.0 D.3.7 4.3 5.10 mL pH3a mLb mL,pH5,A.a=b=100 mL B.a=b=1000 mL 570C.a b 6.99mL0.1mol/L 101mL0.05mol/L c(H+)A.0.5X(108+101)mol/L C.(1 X10
2、-5 40)rnol/L(108+10 1)mol/L-11 D.1 40 mol/L B.7pH=8NaOHpH=10NaOHpHA.8.3 B.8.xL pH=aC.9 D.9.7 yL pH=bax/yA.1 9.-14-a-b B.10/a pH=apH=ba+b-14 C.10/a a-b D.10/a 1.pH=127 1 A.1.0X10 mol L-2 1 C.1.0X 10 mol L 2.1mL0.1 mol/L A.1 x 104 mol/L-11 C.1 X 10 mol/L 3pH5a+b-12 rtZ a+b-14 rtZ 12-a-b rtZ 14-a-b rtZ
3、 A.10%B.10%C.10%D.10%10.0.01mol/LH 2SO40.01mol/LNaOH 100mLo 1H2SO4;1H2SO4(10.05mL)0c(H)3 4A.10 B.50 C.5X 10 D.1011.pHXZpHXYZA.X=Y=Z B.X Y=Z C.X Y=Z D.X=YZ12.CHsCOONaNa CHsCOCTA.HCIB.NaOHC.KCID.KOH 13.A.NaNO2pH7 B.HNO 2C.HNO2NaCID.0.1mol/LHNO 2pH2.14514.pH=13pH=2pH=11,A.11:1 B.9:1 C.1:11 D.1:9 570 1
4、2 3 4 5 6 7 8 9 10 11 12 13 14 3015.3NaHC0 3O.1mol/L 16.617.5pH=2HnA(A)pH=12B(OH)mpH=8 12 18.(16)570 1 2 3 4 5 6 7 8 9 10 11 12 13 14 CD D C A C D D C A D B D AD D 1.pH=12DpH=12c(H c(OH)c(H)=10 pH 12 1 2 1c(H)=1.0 X 10 mol L c(OH)=1.0 x 10 mol L(1)H c(OH)=c(H J=1.0 x 1012 mol L 1(2)OH c(OH)=1.0X 102
5、 mol L 1CD2.()c(H+)=1X 10-3L x 0.1mol/L/2L=1 x 10-4mol/L-14-4-10c(OH)=1 x 10/1 x 10=1 x 10 mol/LD3.c(H+)=2 x 10-8mol L-1c(SO42-)=10-8 mol L-1B1x 10-7mol L-11 x 10-7mol L-1C4.HYci 3 1c(H)=x 10 mol L 2 pH=3 lg2=3.3HYH c(H)x 103 mol L 1 pH v 3.3 2 A5.H+c(H+)c(H+)H+c(H+)c(H+)n(H+)Vac(H+)c(H+)c(H+)b a:C6
6、.101mLBa(OH)299mL2mL 99mLBa(OH)299mL2mL0.05mol/LBa(OH)2200mLOH-H+D D 8.c(HCl)=c(H+)=10-amol-L-1=10一ax x mol-L-1,c(NH 3 a=c(OH-)=10b-14 mol L-1NH3 0 10“14a x y mol L-1 10-a-x=10b-14 a x y,x/y=10a+b-14/a C9.1Lc(OH-)=10-1410-a mol L-1=10a-14mol L-1 OH-10a-14molNH3 0=10-bmol L-1 x 1L=10-bmol10a+b-12%。A1
7、0.1H2SO4,10.05mL100mL1H2SO4NaOH2NaOH100mL 1 c(H+)=0.05 0.01 2=10-5(mol/L)100 1 c(OH-)0.05 0.01 2=10-5(mol/L)100 c(H+)=KW=10-9(mol/L)104 c(OH 10,D15HCO3-+H2O-H2CO3+OH-c(OH-)32 2 16c(C03-)C03-0H-2CO32-CO32-+H2O=HC03-+0H-BaCBa2+CO32-=BaCO3 c(C032-)C032-c(0H-)4 17.1BnAm 1 2An-;1 An-+H20 HAn-1+OH-3 18.1 6(7)(8)2