2022年周衍柏《理论力学》第五章教案-分析力学 .pdf

上传人:Q****o 文档编号:60281515 上传时间:2022-11-15 格式:PDF 页数:6 大小:214.87KB
返回 下载 相关 举报
2022年周衍柏《理论力学》第五章教案-分析力学 .pdf_第1页
第1页 / 共6页
2022年周衍柏《理论力学》第五章教案-分析力学 .pdf_第2页
第2页 / 共6页
点击查看更多>>
资源描述

《2022年周衍柏《理论力学》第五章教案-分析力学 .pdf》由会员分享,可在线阅读,更多相关《2022年周衍柏《理论力学》第五章教案-分析力学 .pdf(6页珍藏版)》请在得力文库 - 分享文档赚钱的网站上搜索。

1、第五章分析力学本章要求(1)掌握分析力学中的一些基本概念;(2)掌握虚功原理;(3)掌握拉格朗日方程;(4)掌握哈密顿正则方程。第一节约束和广义坐标一、约束的概念和分类 加于力学体系的限制条件叫约束。按不同的标准有不同的分类:按约束是否与时间有关分类:稳定约束、不稳定约束;按质点能否脱离约束分类:可解约束、不可解约束;按约束限制范围分类:几何约束(完整约束)、运动约束(不完整约束)。本章只讨论几何约束(完整约束),这种约束下的体系叫完整体系。二、广义坐标 1、自由度描述一个力学体系所需要的独立坐标的个数叫体系的自由度。设体系有n 个粒子,一个粒子需要3 个坐标(如 x、y、z)描述,而体系受有

2、K个约束条件,则体系的自由度为(3n-K)2、广义坐标描述力学体系的独立坐标叫广义坐标。例如:作圆周运动的质点只须角度用描述,广义坐标为,自由度为1,球面上运动的质点,由极角和描述,自由度为2。第二节虚功原理本节重点要求:掌握虚位移、虚功、理想约束等概念;掌握虚功原理。一、实位移与虚位移质点由于运动实际上所发生的位移叫实位移;在某一时刻,在约束允许的情况下,质点可能发生的位移叫虚位移。如果约束为固定约束,则实位移是虚位移中一的个;若约束不固定,实位移与虚位移无共同之处。例如图5.2.1 中的质点在曲面上运动,而曲面也在移动,显然实位移与虚位移不一致。二、理想约束设质点系受主动力和约束力的作用,

3、它们在任意虚位移中作的功叫虚功。若约束反力在任意虚位移中对质点系所作虚功之和为零,则这种约束叫理想约束。光滑面、光滑线、刚性杆、不可伸长的绳等都是理想约束。三、虚功原理 1、文字叙述和数学表示:受理想约束的力学体系,平衡的充要条件是:作用于力学体系的诸主动力在任意虚位移中作的元功之和为零。即(1)适用条件:惯性系、理想不可解约束。2、推论设系统的广义坐标为q1,qa,qS,虚位移可写为用广义坐标变分表示的形式:定义:称为相应于广义坐标qa的广义力,则虚功原理表述为:理想约束的力学体系平衡的充要条件为质点系受的广义力为零,即:文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S

4、9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H

5、3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:

6、CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K

7、7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10

8、 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A

9、1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K

10、8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3(2)3、用虚功原理求解平衡问题的方法步骤一般步骤为:(1)确定自由度,选取坐标系,分析力(包括主动力、约束力);(2)选取广义坐标并将各质点坐标表示成广义坐标qa的函数:;(3)求主动力的虚功并令其为零:,由此求出平衡条件。例 见书 P

11、276 例 1第三节拉格朗日方程本节重点要求:(1)掌握拉格朗日方程的两种形式,方程的特点和适用条件等;(2)掌握用拉格朗日方程求解具体问题的步骤;(3)了解循环积分等概念。一、基本形式的拉格朗日方程 1、方程的推导由牛顿第二定律并应用理想约束的条件,可以得到达朗伯拉格朗日方程:(1)将坐标的变分改成用广义坐标q1,qS的变分表示,即:经数学运算,令(称为体系的动能),(称为相应于 qa的广义力),则(1)式变文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K

12、2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D

13、10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS1

14、0A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B

15、3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY

16、5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X

17、2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编

18、码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3为:(2)这就是基本形式的拉格朗日方程,应注意:(2)实际是一组方程。2、方程的适用条件:理想约束。二、保守系的拉格朗日方程设作用于体系的力全为保守力,则广义力可由(V为势能)求得:在普遍形式的拉氏方程(2)中,由于 V不包含广义速度,可令:(动能与势能的差)为拉格朗日函数,则(2)式变为:(3)应指出(3)的适用条件为保守系,理想约束,且(3)应用很

19、普遍。三、应用拉格朗日方程求解问题的步骤,例一般步骤:画草图,确定自由度 s 和广义坐标 qa;分析主动力,若为保守系,则求出势能 V;若为非保守力,则计算广义力 Qa;求动能 T=T();对保守系,求出 L=T-V,进而代入方程(3),写出运动方程;对非保守系,将 T和广义力 Q 代入方程(2),写出运动方程。解方程,求出q(t)。例 1 P265 4.10题圆环在光滑圆圈上运动,而圆圈绕垂直圆面的轴作匀角速运动,求圆环运动规律。文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2

20、H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码

21、:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2

22、K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D1

23、0 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10

24、A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3

25、K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5

26、S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3解:方法一:牛顿力学方法(已在第四章第三节作为举例计算)方法二:用拉格朗日方程求解。这是光滑圆圈且受的力只有重力和约束力,属于保守体系,可采用保守系的拉氏方程求解。质点自由度为1,转角为广义坐标,广义速度为。任一角度时圆环(视为质点)的动能,其中绝对速度 v 可由速度合成公式求出:这里(方向沿切线方向),牵连速度,大小为,方向垂直

27、于 op。由速度合成公式得到:动能:取圆平面为零势能位置,则V=0,从而 L=T-V=T-0=T 代入拉氏方程(2)中:,得到四、循环积分。若拉氏函数L 中某一坐标 qi不出现,则该坐标qi叫循环坐标,则(常数),叫循环积分。第五节 哈密顿正则方程本节不作重点要求。基本要求是:了解正则坐标、正则动量的概念和正则方程及其应用。一、哈密顿函数 设力学体系的广义坐标为,广文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 Z

28、Y5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6

29、X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档

30、编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1

31、K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4

32、D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS

33、10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6

34、B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3义速度为,则拉格朗日函数,定义广义动量,则函数叫哈密顿函数。它是广义坐标、广义动量的函数,而广义坐标、广义动量称为正则变量。特例:对保守体系,H=T+V (动能与势能之和)二、哈密顿正则方程 哈密顿函数满足的方程为:由该方程组也可探讨运动规律。方程组(1)叫哈密顿正则方程。三、用哈密顿正则方程求解问题的步骤一般步骤为:确定自由度r 和广义坐标求动能 T和势能 V,写出拉格朗日函数。求广义动量,将

35、T和 V中的换为,写出 H=T+V=H(,)、写出正则方程,进而解方程。例电子的运动(见书P314-316)最后指出:拉格朗日方程和哈密顿正则方程都是分析力学中的基本方程,其作用与牛顿第二定律一样,其中拉氏方程为二阶微分方程,哈密顿正则方程为一阶微分方程,但个数比前者多一倍。文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9

36、D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3

37、文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:C

38、U1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7

39、H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10

40、HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1

41、F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3文档编码:CU1K2K7H4D10 HS10A1F6B3K8 ZY5S9D6X2H3

展开阅读全文
相关资源
相关搜索

当前位置:首页 > 教育专区 > 高考资料

本站为文档C TO C交易模式,本站只提供存储空间、用户上传的文档直接被用户下载,本站只是中间服务平台,本站所有文档下载所得的收益归上传人(含作者)所有。本站仅对用户上传内容的表现方式做保护处理,对上载内容本身不做任何修改或编辑。若文档所含内容侵犯了您的版权或隐私,请立即通知得利文库网,我们立即给予删除!客服QQ:136780468 微信:18945177775 电话:18904686070

工信部备案号:黑ICP备15003705号-8 |  经营许可证:黑B2-20190332号 |   黑公网安备:91230400333293403D

© 2020-2023 www.deliwenku.com 得利文库. All Rights Reserved 黑龙江转换宝科技有限公司 

黑龙江省互联网违法和不良信息举报
举报电话:0468-3380021 邮箱:hgswwxb@163.com