2022年惠州市2018届高三第二次调研考试理科数学 .pdf

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1、惠州市 2018 届高三第二次调研考试理科数学一、选择题：共12 小题，每小题5 分，共 60 分每小题给出的四个选项中，只有一项符合题目要求1若21zii(i为虚数单位)，则复数z在复平面内对应的点在（）A第一象限B第二象限C第三象限D第四象限2已知集合Ax xa，2320Bx xx，若ABB，则实数a的取值范围是（）A1aB1aC2aD2a3设为三条不同的直线，为一个平面，下列命题中正确的个数是（）若，则与相交；若则；若ml/，nm/，l，则；若ml/，则nl/A1B2C3D44“不等式在上恒成立”的一个必要不充分条件是（）ABCD5设随机变量服从正态分布4,3N，若51PaPa，则实数a

2、等于（）A7B6C5D46 周易历来被人们视作儒家群经之首，它表现了古代中华民族对万事万物的深刻而又朴素的认识，是中华人文文化的基础，它反映出中国古代的二进制计数的思想方法我们用近代术语解释为：把阳爻“”当作数字“1”，把阴爻“”当作数字“0”，则八卦所代表的数表示如下：依次类推，则六十四卦中的“屯”卦，符号“”表示的十进制数是（）A18B17C16D157 已知等差数列na的前n项和为nS，且91 2162aa，24a，则数列1nS的前10项和为（）A1112B1011C910D898旅游体验师小明受某网站邀请，决定对甲、乙、丙、丁这四个景区进行体验式旅游，若甲景区不能最先旅游，乙景区和丁景

3、区不能最后旅游，则小李旅游的方法数为（）A24B18C16D109已知A，B为双曲线E的左右顶点，点M在双曲线E上，ABM为等腰三角形，且顶角为120，则双曲线E的离心率为（）A5B2C3D210某三棱锥的三视图如图所示，且三个三角形均为直角三角形，则xy最大值为（）A32B32 7C64D64 711函数()sin(2)fxAx,02A部分图像如图所示，且，对不同的，若，有，则（）nml,ll，nlmlnmlnmn20 xxmR41m10m0m1m0)()(bfafbaxx,21)()(21xfxf3)(21xxf卦名符号表示的二进制数表示的十进制数坤000 0 震001 1 坎010 2

4、兑011 3 A在上是减函数B在上是增函数C在上是减函数D在上是增函数12函数)(xf是定义在R上的奇函数，当0 x时，|1|2102()12(2)2xxf xxf x，则函数1)()(xxfxg在),6上的所有零点之和为（）A8B32C81D0二填空题：本题共4小题，每小题 5分，共 20分13已知1tan2，且3,2，则cos2_ 14某班共有56人，学号依次为56,3,2,1，现用系统抽样的方法抽取一个容量为4的样本，已知学号为2，30，44的同学在样本中，则还有一位同学的学号应为_ 15已知数列na满足)(22,111Nnaaannn，则数列na的通项公式为na_ 16 在四边形ABC

5、D中，ABDC，已知8,5ABAD，AB与AD的夹角为，且11cos=20，3CPPD，则AP BP_ 三解答题：共70分，解答应写出文字说明，证明过程或演算步骤17（本小题满分12 分）已知ABC中，角,A B C的对边分别为,a b c，2coscoscos0C aCcAb（1）求角C的大小；（2）若2b，2 3c，求ABC的面积)(xf)12,125()(xf)12,125()(xf)65,3()(xf)65,3(文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档

6、编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文

7、档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2

8、文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N

9、2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10

10、N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T1

11、0N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T

12、10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N218（本小题满分12 分）如图，四棱锥PABCD中，底面ABCD是边长为2的菱形，60ABC，PAPB，2PC（1）求证：平面PAB平面ABCD；（2）若PAPB，求二面角APCD的余弦值19（本小题满分12 分）某学校为了丰富学生的业余生活，以班

13、级为单位组织学生开展古诗词背诵比赛，随机抽取题目，背诵正确加10分，背诵错误减10分，背诵结果只有“正确”和“错误”两种。其中某班级背诵正确的概率为23p，背诵错误的概率为13q，现记“该班级完成n首背诵后总得分为nS”（1）求620S且01,2,3iSi的概率；（2）记5S，求的分布列及数学期望文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1

14、U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E

15、1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9

16、E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS

17、9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 H

18、S9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2

19、HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2

20、 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N220（本小题满分12 分）已知点C为圆22(1)8xy的圆心，P是圆上的动点，点Q在圆的半径CP上，且有点A(1,0)和AP上的点M，满足0MQAP，2APAM（1）当点P在圆上运动时，求点Q的轨迹方程；（2）若斜率为k的直线l与圆221xy相切，与（1）中所求点Q的轨迹交于不同的两点HF,，O是坐标原点，且3445OF OH时，求k的取值范围21（本小题满分12 分）已

21、知函数223xfxexa，aR（1）若函数yfx的图象在0 x处的切线与x轴平行，求a的值；（2）若0 x，0fx恒成立，求a的取值范围文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2

22、HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2

23、 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V

24、2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5

25、V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X

26、5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5

27、X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A

28、5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2选考题：共 10分。请考生在第22、23题中任选一题作答。如果多做，则按所做的第一题计分22（本小题满分10 分）选修 4-4：坐标系与参数方程 已知曲线2cos:3sinxCy（为参数）和定点(0,3)A，1F、2F是此曲线的左、右焦点，以原点O为极点，以x轴的正半轴为极轴建立极坐标系（1）求直线2AF的极坐标方程；（2）经过点1F且与直线2AF垂直的直线交此圆锥曲线于M、N两点，求11|MFNF的值23（本小题满分10 分）选修 4-5：不等式选讲 已知函数()|1|1|f xmxx（1）当时，求不等式的解集；（2）若二次函数

29、与函数的图象恒有公共点，求实数的取值范围5m()2fx223yxxyfxm文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:

30、CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码

31、:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编

32、码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档

33、编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文

34、档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2

35、文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N

36、2惠州市 2018 届高三第二次调研考试理科数学参考答案一、选择题：（每小题5 分，共 60 分）1【解析】由题意知123ziii，其对应点的坐标为3,1，在第一象限2【解析】集合232012Bx xxxx，由ABB可得BA，2a.3【解析】错，正确.4【解析】“不等式在上恒成立”0即140m，14m，同时要满足“必要不充分”，在选项中只有“”符合.5【解析】由随机变量服从正态分布4,3N可得对称轴为4x，又5Pa1Pa，5xa与1xa关于4x对称，518aa，即6a.6【解析】由题意类推，可知六十四卦中的“屯”卦符合“”表示二进制数的010001，转化为十进制数的计算为0123451 20

37、20 20 21 20 2177【解析】由912162aa及等差数列通项公式得1512ad，又24a，12a，2d，2nSnn，111111nSn nnn，121011111111=12231011SSS110111118【解析】第1 种：甲在最后一个体验，则有33A种方法；第2 种：甲不在最后体验，则有1222CA种方法，所以小明共有31232210ACA.9【解析】设双曲线方程为222210,0 xyabab，不妨设点 M 在第一象限，所以2ABBMa，120MBA，作MHx轴于点H，则60MBH，故BHa，3MHa，所以2,3Maa，将点M代入双曲线方程22221xyab，得ab，所以2

38、e.10【解析】依题意，题中的几何体是三棱锥P-ABC(如图所示)，其中底面ABC 是直角三角形，ABBC，PA面 ABC，2 7BC，22210PAy，2222 7PAx，因此222222128102 7128642xxxyxxxx，当且仅当22128xx，即8x时取等号，因此xy 的最大值是64.11【解析】由题意22T，2A，2ba，又，有，123sin 22xx，即12223xx，且12sin 212xx，即20 xxmR0m)()(21xfxf3)(21xxf题号1 2 3 4 5 6 7 8 9 10 11 12 答案A D C C B B B D D C B A 文档编码:CS8

39、E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS

40、8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:C

41、S8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:

42、CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码

43、:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编

44、码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档

45、编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N212222xx，解得3，2sin23fxx，222,232kxkkZ，yfx单调递增.解

46、得5,1212kxkkZ.所以选项 B 符合.12【解析】令()()10g xxfx，所以求yg x的零点之和yfx和1yx的交点横坐标之和，分别作出0 x时，yfx和1yx图象，如图由于yfx和1yx都关于原点对称，因此6,6x的零点之和为0，而当8x时，18fx，即两函数刚好有1 个交点，而当8,x时1yx的图象都在yfx的上方，因此零点之和为8.二填空题：本题共4小题，每小题 5分。135514.16 15.12nn16.2 13【解析】55；cossin2，由3,2且1tan2可得5sin5.14【解析】由题意得，需要从 56 人中分成4 组，每组的第2 位学号为抽出的同学，所以有1

47、14216.15【解析】由122nnnaa两边同除12n可得111222nnnnaa，又1122a，2nna成以12为首，公差为12的等差数列，1112222nnann，12nnan.16 【解 析】3CPPD，14APADAB，34BPADAB，又8AB，5AD2131442AP BPADABADABADAD AB2316AB，代 入 式 子 可 得2AP BP三解答题：共70分，解答应写出文字说明，证明过程或演算步骤。17.解：（1）2coscoscos0C aCcAb，由正弦定理可得2cossincossincossin0CACCAB2 分2cossinsin0CACB，即2cossin

48、sin0CBB又0180B，sin0B，1cos2C，即120C.6 分（2）由余弦定理可得22222 3222 cos12024aaaa，9 分文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5

49、X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A

50、5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9A5X5V2 HS9E1U10U7A10 ZO9H9B4T10N2文档编码:CS8E9