2022年中考数学压轴题全揭秘系列专题51新定义和阅读理解型问题 .pdf

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1、新定义和阅读理解型问题在近年的全国各地的中考试题中频频出现，特别引人注目，这些试题不再囿于教材的内容及其方法，以新颖别致的取材、富有层次和创造力的设问独树一帜这些试题中还常常出现新的概念和方法，不仅要求学生理解这些新的概念和方法，而且要灵活运用这些新的概念和方法去分析、解决一些简单的问题。在新定义和阅读理解型问题中，除了考查学生的分析分析、综合、抽象、概括等演绎推理能力，即逻辑推理能力外，还经常考查学生的观察、猜想、不完全归纳、类比、联想等合情推理能力，考查学生的直觉思维。因此，这类问题需要学生通过对阅读材料的阅读理解，然后进行合情推理，就其本质进行归纳加工、猜想、类比和联想，作出合情判断和推

2、理，前面诸专题对存在性探究问题型进行了命题，后面将有专题对规律探究型问题进行命题。本专题原创编写新定义和阅读理解型问题模拟题。原创模拟预测题1.阅读下面的材料：小明在数学课外小组活动中遇到这样一个“新定义”问题：0210.abbaabbb；定义运算“：”求为的值.小明是这样解决问题的：由新定义可知a=1，b=-2，又 b 0，所以 1（-2）=12请你参考小明的解题思路，回答下列问题：（1）计算：23=；（2）若 5m=56，则 m=（3）函数 y=2 x（x0）的图象大致是（）yxOyxOyxOyxO【答案】解：（1）23（2）6 （3）D【解析】考点：规律探索应用，反比例函数的图像原创模拟

3、预测题2.我们新定义一种三角形：两边平方和等于第三边平方的两倍的三角形叫做奇异三角形（1）根据“奇异三角形”的定义，请你判断命题“等边三角形一定是奇异三角形”是真命题还是假命题?（2）在 RtABC中，ACB=90，AB=c，AC=b，BC=a，且 ba，若 RtABC是奇异三角形，求 a：b：c；（3）如图，AB是 O的直径，C是 O上一点（不与点A，B重合），D是半圆ADB的中点，C，D在直径 AB的两侧，若在O内存在点E，使 AE=AD，CB=CE 求证：ACE是奇异三角形；当 ACE是直角三角形时，求AOC的度数【答案】（1）真命题（2）a：b：c=1：2：3（3）见解析 60或120

4、【解析】文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档

5、编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6

6、V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R1

7、0M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS

8、10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2

9、P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 Z

10、B6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V82：1 然后分两种情况讨论.试题解析：解：（1）真命题（2 分）（3）在 RtABC中，a2+b2=c2，证明：AB是 O的直径，ACB=ADB=90，在 Rt

11、ACB中，AC2+BC2=AB2；在 RtADB中，AD2+BD2=AB2D是半圆ADB的中点，BDAD，AD=BD，（6 分），AB2=AD2+BD2=2AD2，（7 分）又 CB=CE AE=AD，AC2+CE2=2AE2ACE是奇异三角形（8 分）文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:

12、CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E

13、6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9

14、 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T

15、9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T

16、4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N

17、9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V

18、8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8考点：1.命题；2.勾股定理；3.圆周角定理及推论；4.直角三角形的性质.原创模拟预测题3.阅读理解：对于任意正实数a、b，(ab)20，a2abb0，ab2ab，只有当ab时，等号成立.结论：在ab 2ab（a、b均为正实数）中，若ab为定值p，则a+b2p，只有当ab时，ab有最小值2p.根据上述内容，回答下列问题：（1）若m0，只有当m时，mm有最小值；若m0，只有当m时，2mm有最小值 .文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10

19、M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS1

20、0T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P

21、7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB

22、6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T

23、2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编

24、码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V

25、6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8（2）如图，已知直线L1：y21x 1 与x轴交于点A，过点A的另一直线L2与双曲线yx（x0）相交于点B（2，m），求直线L2的解析式.（3）在（2）的条件下，若点C为双曲线上任意一点，作CDy轴交直线L1于点D，试求当线段CD最短时，点A、B、C、D围成的四边形面积.【答案】（

26、1）当1m时，mm1有最小值为2；当2m时，mm82有最小值为8（2）2xy（3）23 A（-2，0）又点 B（2，m）在)0(8xxy上，)4,2(,4 Bm设直线2L的解析式为：bkxy，则有，4202bkbk解得：21bk直线2L的解析式为：2xy；文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码

27、:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6

28、E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M

29、9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10

30、T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7

31、T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6

32、N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2

33、V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V82311122)65(214621原创模拟预测题4.如图是一组密码的一部分为了保密，许多情况下可采用不同的密码，请你运用所学知识找到破译的“钥匙”。目前，已破译出“正做数学”的真实意思是“祝你成功”。若“正”所处的位置为（x，y），你找到的密码钥匙是，破译的“今天考试”真实意思是。【答案】对应文字横坐标减1，纵坐标减2；努力发挥。【考点】探索规律题（图形的变化类），坐标的变换。文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9

34、V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4

35、 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9

36、A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8

37、文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:C

38、V6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6

39、R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9

40、HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8原创模拟预测题5.对于实数x，我们规定x表示不大于x 的最大整数，如44,31,2.53，现对82进行如下操作：18293829313823第 次第 2次第3次，这样对 82 只需进行3 次操作后变为 1，类似地，对121 只需进行次操作后变为1；只需进行3 次操作后变为1 的所有正整数中，最大的是

41、 .【答案】3；255。【考点】新定义，无理数的大小比较，解一元一次不等式组。原创模拟预测题6.初三年级某班有54 名学生，所在教室有6 行 9 列座位，用(m,n)表文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:C

42、V6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6

43、R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9

44、HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9

45、V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4

46、 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9

47、A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8

48、示第 m 行第 n 列的座位，新学期准备调整座位，设某个学生原来的座位为(m,n)，如果调整后的座位为(i,j)，则称该生作了平移a,bmi,nj,并称ab+为该生的位置数。若当m n36时，mn 取得最小值，则该生位置数的最大值为 。【答案】10。【考点】坐标与图形的平移变化，坐标确定位置。原创模拟预测题7.阅读下列文字与例题将一个多项式分组后，可提公因式或运用公式继续分解的方法是分组分解法。例如：（1）am anbmbnambman bnm ab()n ababm(n)()，（2）222222xy2y1xy2y1xy1xy1xy 1。试用上述方法分解因式224x2xyy。【答案】2xy2x

49、y 1。【考点】分组分解法因式分解。【分析】22224x2xyy4xy2xy2xy2xy2xy2xy2xy1。原创模拟预测题8.设 a、b 是任意两个不等实数，我们规定：满足不等式axb的实数x 的所有取值的全体叫做闭区间，表示为a，b对于一个函数，如果它的自变量x 与函数值 y 满足：当 m xn 时，有 m yn，我们就称此函数是闭区间m，n上的“闭函数”文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N

50、9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V8文档编码:CV6V6E6R10M9 HS10T9V2P7T4 ZB6N9A1T2V