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1、含参变量的分离与讨论解题思路1.转化为所给变量的函数,利用函数知识解决问题2.从关系式中分离出变量,利用题中所给已知变量的条件求出另一侧函数的范围,从而确定所求变量知识链接1.若不等式x2+ax+10,对于一切x 0,21都成立,则a的最小值是2.已知 f(t)=2t,t2,8,对于 f(t)值域内的所有实数m,不等式x2+mx+42m+4x恒成立,则x 的范围是3.已知以 T=4 为周期的函数f(x)=m21x,x(-1,1 1-2x,x(1,3 其中 m0,若方程 3f(x)=x 恰有 5 个实数解,则m 的取值范围为4.已知集合 A=x/x2-3x+2=0,B=x/x2-ax+a-1=0
2、,C=x/x2-mx+2=0,且 AB=A,AC=C,则 a 的值为,m 的取值范围为5.若不等式(1-a)n-alga0 且 a1,试求使方程2 a(x-ak)=a(x2-a2)有解时 k 的取值范围文档编码:CU1F2X4L4C5 HL3W3F7M6A5 ZO6N3Z6P4E9文档编码:CU1F2X4L4C5 HL3W3F7M6A5 ZO6N3Z6P4E9文档编码:CU1F2X4L4C5 HL3W3F7M6A5 ZO6N3Z6P4E9文档编码:CU1F2X4L4C5 HL3W3F7M6A5 ZO6N3Z6P4E9文档编码:CU1F2X4L4C5 HL3W3F7M6A5 ZO6N3Z6P4E
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4、3W3F7M6A5 ZO6N3Z6P4E9文档编码:CU1F2X4L4C5 HL3W3F7M6A5 ZO6N3Z6P4E9文档编码:CU1F2X4L4C5 HL3W3F7M6A5 ZO6N3Z6P4E9文档编码:CU1F2X4L4C5 HL3W3F7M6A5 ZO6N3Z6P4E9文档编码:CU1F2X4L4C5 HL3W3F7M6A5 ZO6N3Z6P4E9文档编码:CU1F2X4L4C5 HL3W3F7M6A5 ZO6N3Z6P4E9文档编码:CU1F2X4L4C5 HL3W3F7M6A5 ZO6N3Z6P4E9文档编码:CU1F2X4L4C5 HL3W3F7M6A5 ZO6N3Z6P4E
5、9文档编码:CU1F2X4L4C5 HL3W3F7M6A5 ZO6N3Z6P4E9文档编码:CU1F2X4L4C5 HL3W3F7M6A5 ZO6N3Z6P4E9文档编码:CU1F2X4L4C5 HL3W3F7M6A5 ZO6N3Z6P4E9文档编码:CU1F2X4L4C5 HL3W3F7M6A5 ZO6N3Z6P4E9文档编码:CU1F2X4L4C5 HL3W3F7M6A5 ZO6N3Z6P4E9文档编码:CU1F2X4L4C5 HL3W3F7M6A5 ZO6N3Z6P4E9文档编码:CU1F2X4L4C5 HL3W3F7M6A5 ZO6N3Z6P4E9文档编码:CU1F2X4L4C5 HL
6、3W3F7M6A5 ZO6N3Z6P4E9文档编码:CU1F2X4L4C5 HL3W3F7M6A5 ZO6N3Z6P4E9文档编码:CU1F2X4L4C5 HL3W3F7M6A5 ZO6N3Z6P4E9文档编码:CU1F2X4L4C5 HL3W3F7M6A5 ZO6N3Z6P4E9文档编码:CU1F2X4L4C5 HL3W3F7M6A5 ZO6N3Z6P4E9文档编码:CU1F2X4L4C5 HL3W3F7M6A5 ZO6N3Z6P4E9文档编码:CU1F2X4L4C5 HL3W3F7M6A5 ZO6N3Z6P4E9文档编码:CU1F2X4L4C5 HL3W3F7M6A5 ZO6N3Z6P4E
7、9文档编码:CU1F2X4L4C5 HL3W3F7M6A5 ZO6N3Z6P4E9文档编码:CU1F2X4L4C5 HL3W3F7M6A5 ZO6N3Z6P4E9文档编码:CU1F2X4L4C5 HL3W3F7M6A5 ZO6N3Z6P4E9文档编码:CU1F2X4L4C5 HL3W3F7M6A5 ZO6N3Z6P4E9文档编码:CU1F2X4L4C5 HL3W3F7M6A5 ZO6N3Z6P4E9文档编码:CU1F2X4L4C5 HL3W3F7M6A5 ZO6N3Z6P4E9文档编码:CU1F2X4L4C5 HL3W3F7M6A5 ZO6N3Z6P4E9文档编码:CU1F2X4L4C5 HL3W3F7M6A5 ZO6N3Z6P4E9文档编码:CU1F2X4L4C5 HL3W3F7M6A5 ZO6N3Z6P4E9文档编码:CU1F2X4L4C5 HL3W3F7M6A5 ZO6N3Z6P4E9文档编码:CU1F2X4L4C5 HL3W3F7M6A5 ZO6N3Z6P4E9文档编码:CU1F2X4L4C5 HL3W3F7M6A5 ZO6N3Z6P4E9文档编码:CU1F2X4L4C5 HL3W3F7M6A5 ZO6N3Z6P4E9