反函数(含答案).pdf

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1、反函数一些结论:1定义域上的单调函数必有反函数;2奇函数若存在反函数,则其反函数也是奇函数;3定义域为非单元素集的偶函数不存在反函数.4周期函数在整个定义域内不存在反函数.(5)互为反函数的两个函数具有相同的单调性考点一。反函数图象1.已知函数的反函数是,则的图象是()解:由题意知则所以的图象可由的图象向右平移1 个单位而得到。故选(C)。考点二。求反函数定义域,值域2.(1)若为函数的反函数,则的值域为 _。解:利用反函数的值域就是原函数的定义域,立即得的值域为。(2)已知 p 为xe2y上一点,Q为2lnlnyx上一点,求PQ最小值。解:由题,两函数互为反函数,当PQ与 y=x 垂直,且

2、P,Q 分别为两曲线切点时,PQ最小。2lnlnyx,则1x1y,即 x=1,切点为(1,-ln2),故22ln1d。由对称性,PQ最小值=)2ln12(。(3)已知 y=a 与 y=2(x+1),y=x+lnx交于 A,B两点,求AB最小值。解:0 x11y,单调递增,y=2(x+1)单增且 k=2,画图像得:要使AB最小,只需B 到 y=2(x+1)距离 d 最小又5535212d,故ABmin=d25=23。考点三。求反函数3.(1)函数的反函数是()A.B.C.D.解:由可得,故从解得因所以即其反函数是故选(B)。(2)求下列函数的反函数:(1)2()(1)f xxx x;(2)221

3、(01)()(10)xxf xxx.解:(1)由2(1)yxx x得2211()(1)24yxx,211(0)24xyy,所求函数的反函数为211(0)24yxx(2)当01x时,得1(10)xyy,当10 x时,得(01)xyy,所求函数的反函数为1(10)(01)xxyxx(3)f(x)图像与 g(x)图像关于直线x+y=0 对称,则f(x)反函数为()A.y=g(x)B.y=g(-x)C.y=-g(x)D.y=-g(-x)解:f(x)图像与 g(x)图像关于直线x+y=0 对称,-x=f(-y),即-y=)(f1x,则 y=-)(f1x,)()(f1xgx,故)(-g(f1xx),选 D

4、.考点四。反函数与方程4.已知函数,则方程的解 x=_。解:当函数存在反函数时,若,则。所以只需求出的值即为中的 x的值。易知,所以即为所求的值。文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B

5、8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1

6、R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL

7、4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO

8、5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3

9、W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:

10、CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1考点五。反函数求参数5.(1)y=f(x)是xay的反函数,且过点),a2a(,求 a 的值。解:由题y=f(x)=x

11、alog,将),a2a(代入得:a=2.(2)函数11(,)1axyxxRaxa的图象关于yx对称,求a的值解:由11(,)1axyxxRaxa得1(1)(1)yxya y,11()(1)(1)xfxxa x,由题知:1()()f xfx,11(1)1xaxa xax,1a(3)若(2,1)既在()f xmxn的图象上,又在它反函数图象上,求,m n的值解:(2,1)既在()f xmxn的图象上,又在它反函数图象上,(1)2(2)1ff,221mnmn,37mn(4)已知 y=f(x)与ax2y关于 y=-x 对称,且f(-2)+f(-4)=1,求 a 的值。解:设y=f(x)上点M),x00

12、y(,关于y=-x对称点为N),y-00 x(,代入ax2y中,则ay02x-0,即ayx002)(log,)(logy2xa=f(x),又 f(-2)+f(-4)=a-1+a-2=2a-3=1,故 a=2.考点六。反函数的奇偶性,单调性6.函数的反函数是()A.奇函数,在()上是减函数B.偶函数,在()上是减函数C.奇函数,在()上是增函数D.偶函数,在()上是增函数解:函数与具有相同的单调性,奇函数的反函数也为奇函数这两条性质,立即选(C)。考点七。反函数求值7.(1)设函数的图象关于点(1,2)对称,且存在反函数,则_。解:由,可知函数的图象过点(4,0)。而点(4,0)关于点(1,2)

13、的对称点为(-2,4)。由题意知点(-2,4)也在函数的图象上,即有,所以。评注:当函数存在反函数时,若,则。文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X

14、1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3

15、D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5

16、H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O

17、2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9

18、W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8

19、P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1(2)设函数xxxf121)(,又函数)(xg与1(1)yfx的图象关于yx对称,求)2(g的值解:由1(1)yfx得()1xfy,()()1g xf x

20、,(2)(2)12gf考点八。反函数与不等式8.(1)设是函数的反函数,则成立时 x 的取值范围是()A.B.C.D.解:由,知函数在 R上为增函数,所以在 R上也为增函数。故由,有而可得故选(A)。(2)设是函数的反函数,则下列不等式中恒成立的是()A.B.C.D.解:依题意知。画出略图,故选(A)。文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5

21、H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O

22、2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9

23、W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8

24、P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R

25、9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4

26、W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1文档编码:CL4W9W3D4T10 HO5B8P5H9O5 ZR3W1R9O2X1

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