(完整word版)2018年高考南通市数学学科基地密卷(2).pdf

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1、高三数学试卷第 1 页 共 17 页甲乙8 9 79 013 98 210（第 5 题）2018 年高考模拟试卷（2）南通市数学学科基地命题第卷（必做题，共160分）一、填空题：本大题共14 小题，每小题5 分，共 70 分1 已知集合 A=1，4，B=|13xx ，则 AB=2 设复数2(2i)z（i为虚数单位），则z的共轭复数为3 函数的23logyx定义域为4 阅读下面的伪代码，由这个算法输出的结果为5 如图是甲、乙两位同学在5 次数学测试中得分的茎叶图，则成绩较稳定（方差较小）的那一位同学的方差为6 将黑白 2 个小球随机放入编号为1，2，3 的三个盒子中，则黑白两球均不在1 号盒子的

2、概率为7 在平面直角坐标系xOy 中，将函数cos2yx的图象向右平移6个单位得到()g x的图象，则()2g的值为8 在平面直角坐标系xOy中，双曲线2214yx的一条渐近线与准线的交点到另一条渐近线的距离为s0 t1 For I From 1 To 3 ss+I ttI End For rstPrintr（第 4 题）精品资料-欢迎下载-欢迎下载 名师归纳-第 1 页，共 17 页 -高三数学试卷第 2 页 共 17 页9 若tan34x，则sin2cos3sin4cosxxxx的值为10已知函数f(x)是定义在R 上的偶函数，且对于任意的xR 都有 f(x+4)=f(x)+f(2)，f(

3、1)=4，则 f(3)+f(10)的值为11已知nS为数列 an的前 n 项和，且22111nnnaaa，21313Sa，则 an 的首项的所有可能值为12在平面直角坐标系xOy中，已知直线:3450lxy与圆22:100Cxyx交于A，B 两点，P为x轴上一动点，则ABP 周长的最小值为13已知函数22()3xxaxafxxxaxa，记|()0Ax fx，若(2)A I，则实数a的取值范围为14若 ABC 中，AB=2，BC=8，B45，D 为 ABC 所在平面内一点且满足()()4AB ADAC ADuu u r uuu ru uu r uu u r，则 AD 长度的最小值为二、解答题：本

4、大题共6 小题，共90 分请在答题卡指定区域内作答.解答时应写出文字说明、证明过程或演算步骤15（本小题满分14 分）如图，在ABC 中，abc，为ABC，所对的边，CDAB 于 D，且12BDADc（1）求证：sin2sin()CAB；（2）若3cos5A，求tanC的值C A D B（第 15 题）精品资料-欢迎下载-欢迎下载 名师归纳-第 2 页，共 17 页 -文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7

5、K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9

6、V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7

7、K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9

8、V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7

9、K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9

10、V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7

11、K8T7T4高三数学试卷第 3 页 共 17 页h1r h2（第 17 题）4516（本小题满分14 分）在正四棱锥VABCD中，E，F 分别为棱 VA，VC 的中点（1）求证：EF平面 ABCD；（2）求证：平面VBD 平面 BEF17(本小题满分14 分)如图所示的某种容器的体积为90cm3，它是由圆锥和圆柱两部分连接而成，圆柱与圆锥的底面半径都为r cm圆锥的高为h1 cm，母线与底面所成的角为o45；圆柱的高为h2cm已知圆柱底面的造价为2a 元/cm2，圆柱侧面造价为a 元/cm2，圆锥侧面造价为2a 元/cm2（1）将圆柱的高h2表示为底面半径r 的函数，并求出定义域；（2）当容器

12、造价最低时，圆柱的底面半径r 为多少？18（本小题满分16 分）已知在平面直角坐标系xOy 中，椭圆 C：22221(0)yxabab离心率为22，其短轴长为 2（1）求椭圆 C 的标准方程；（2）如图，A 为椭圆 C 的左顶点，P，Q 为椭圆 C 上两动点，直线PO 交 AQ 于 E，A C B D（第 16 题）V E F 精品资料-欢迎下载-欢迎下载 名师归纳-第 3 页，共 17 页 -文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K

13、7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文

14、档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K

15、7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文

16、档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K

17、7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文

18、档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K

19、7T9G2I2 ZL1X7K8T7T4高三数学试卷第 4 页 共 17 页直线 QO 交 AP 于 D，直线 OP 与直线 OQ 的斜率分别为1k，2k，且1212k k，ADDPu uu ruu u r，AEEQu uu ruuu r（，为非零实数），求22的值19（本小题满分16 分）设数列 na的前 n 项和为nS，已知11a，121nnSS（*nN）（1）求证：数列na为等比数列；（2）若数列 nb满足：11b，1112nnnbba 求数列nb的通项公式；是否存在正整数n，使得14niibn成立？若存在，求出所有n 的值；若不存在，请说明理由20（本小题满分16 分）已知函数*()ln

20、kf xxxkN，()1g xcxcR，（1）当1k时，若曲线()yf x 与直线()yg x 相切，求 c 的值；若曲线()yf x 与直线()yg x 有公共点，求c 的取值范围（2）当2k时，不等式2()()f xaxbxg x对于任意正实数x 恒成立，当c 取得最大值时，求a，b 的值PExyOAQD（第 18 题）精品资料-欢迎下载-欢迎下载 名师归纳-第 4 页，共 17 页 -文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T

21、9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编

22、码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T

23、9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编

24、码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T

25、9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编

26、码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T

27、9G2I2 ZL1X7K8T7T4高三数学试卷第 5 页 共 17 页2018 年高考模拟试卷（2）数学(附加题)21【选做题】本题包括A、B、C、D 四小题，请选定两题，并在相应的答题区域内作答A选修 41：几何证明选讲（本小题满分10 分）如图，ABCD 为圆内接四边形，延长两组对边分别交于点E，FM，N 为 AB，CD 上两点，EMEN，点 F 在 MN 的延长线上求证：BFM AFMB选修 42：矩阵与变换（本小题满分10 分）已知在二阶矩阵M对应变换的作用下，四边形ABCD 变成四边形A B C D，其中(1 1)A，(11)B，(11)C，(3 3)A，(1 1)B，(11)D，（

28、1）求矩阵M；（2）求向量 DCuuuu r的坐标C选修 44：坐标系与参数方程（本小题满分10 分）以平面直角坐标系的原点为极点，x 轴的正半轴为极轴，建立极坐标系，两种坐标系中取相同的长度单位已知直线l 的参数方程是xt，yt3(t 为参数)，圆 C 的极坐标方程是 4cos ，求直线l 被圆 C 截得的弦长D选修 45：不等式选讲（本小题满分10 分）F A D C E N M B 精品资料-欢迎下载-欢迎下载 名师归纳-第 5 页，共 17 页 -文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 Z

29、L1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5

30、P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 Z

31、L1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5

32、P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 Z

33、L1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5

34、P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 Z

35、L1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4高三数学试卷第 6 页 共 17 页已知 x0，y0，z0，221xyz，求证：135xyyzzx【必做题】第22 题、第 23 题，每题10 分，共计 20 分请在答卷纸指定区域内作答22（本小题满分10 分）某同学理科成绩优异，今年参加了数学，物理，化学，生物4 门学科竞赛已知该同学数学获一等奖的概率为23，物理，化学，生物获一等奖的概率都是12，且四门学科是否获一等奖相互独立（1）求该同学至多有一门学科获得一等奖的概率；（2）用随机变量X表示该同学获得一等奖的总数，求X的概率分布和数学期望

36、E X 23（本小题满分10 分）已知函数2()1f xxx，记1()()fxf x，当12()()nnnfxff x 时，（1）求证：2()fx 在(1)，上为增函数；（2）对于任意*Nn，判断()nfx 在(1)，上的单调性，并证明精品资料-欢迎下载-欢迎下载 名师归纳-第 6 页，共 17 页 -文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2

37、 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4

38、T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2

39、 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4

40、T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2

41、 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4

42、T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4高三数学试卷第 7 页 共 17 页2018 年高考模拟

43、试卷（2）参考答案一、填空题：本大题共14小题，每小题 5 分，共 70 分1 1【解析】依题意，AB=1 234i【解析】由于2(2i)34iz，所以 z 的共轭复数为34i 30,8【解析】由23log0 x，解得08x4 36【解析】1236s，1236t，输出的结果6636r52【解析】由茎叶图可知，8889909192905x，所以甲的方差为52211()25iisxx；同理乙的方差为4，所以比较稳定的是甲649【解析】所有等可能的基本事件总数为339种，“黑白两球均不在1 号盒子”有224种，所以概率为49712【解析】()cos 23g xx，所以1()cos232g845【解析

44、】一条渐近线2yx 与右准线55x的交点为5 2 5(,)55，其到另一条渐近线2yx的距离为45925【解析】由31tantan2441(3)xx，得sin2costan223sin4cos3tan45xxxxxx10 4【解析】令f(x+4)=f(x)+f(2)中 x=2，得 f(2)=f(2)+f(2)，所以 f(2)=0，又因为 f(x)是定义在 R 上的偶函数，所以f(2)=0，所以 f(x+4)=f(x)，所以 f(x)是周期为4 的周期函数，所以f(3)+f(10)=f(1)+f(2)=f(1)+0=4 113 4，【解析】因为22111nnnaaa，所以22111nnnaaa，

45、所以222211aaa，223321aaa，221313121aaa，将以上各式相加，得2213113112Saaa，又21313Sa，所以211120aa，获解12 14【解析】设直线l 与圆 C 的一个交点B（5，5）关于 x 轴的CxyOBA（第 12 题）PBQ精品资料-欢迎下载-欢迎下载 名师归纳-第 7 页，共 17 页 -文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P

46、6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL

47、1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P

48、6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL

49、1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P

50、6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL1X7K8T7T4文档编码:CH4T5P6V9V1 HT3K7T9G2I2 ZL