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1、Four short words sum up what has lifted most successful individuals above the crowd: a little bit more.-author-dateSAT2-Physics-Dynamic-testKinematics test (SAT2 Level )Dynamics testSection 1: Multiple ChoicesDirections: For each group of questions below, there is a set of five lettered choices, fol
2、lowed by numbered questions. For each question select the one choice in the set that best answers the question and fill in the corresponding circle on the answer sheet. Do not use a calculator. (Questions 1-10 are SAT2 level)1. what is the approximate weight of a 7.5-kilogram mass sitting on the sur
3、face of earth?(A) 7.5 N(B) 0.75 N(C) 75 N(D) 17.5 N(E) 27.5 N2. A 15-kilogram mass is sliding along a frictionless floor with an acceleration of 5 meters per second squared. What is the magnitude of the net force acting on the mass?(A) 15 N(B) 20 N(C) 3 N(D) 75 N(E) 10 N3. A 3-kiligram mass is trave
4、ling at 15 meters per second when friction begings to decelerate it to a stop in 5 seconds. What is the magnitude of the force of friction? (A) 9 N(B) 3 N(C) 45 N(D) 60 N(E) 15 N4. A person is standing on a bathroom scale in an elevator and notices that her weight is less than normal. This means tha
5、t the elevator: (A) must be moving upward(B) must be moving downward(C) must be at rest(D) must have positive acceleration(E) must have negative acceleration5. A mass is sliding down an incline. As the angle of elevation for the incline increases, the magnitude of the component of its weight perpend
6、icular to the incline:(A) increases(B) decreases(C) increases, then decreases(D) decreases, then increases(E) remains the same6. A 4-kilogram mass is accelerated by a horizontal force of 15 newtons. If the magnitude of the acceleration is 3 meters per second squared, how much friction is acting on t
7、he mass?(A) 5 N(B) 15 N(C) 0 N(D) 27 N(E) 3 N 7. In the situation shown in Figure 7, what is the tension in string 1 ?(A) 69.3 N(B) 98 N(C) 138.6 N(D) 147.6 N(E) 155 N Figure 7 Figure 88. Two masses, M and m, (as shown in Figure 8) are hung over a massless, frictionless pulley as shown below. If Mm,
8、 what is the downward acceleration of mass M?(A) g(B) (M-m)g/(M+m)(C) (M/m)g(D) Mmg/(M+m)(E) Mmg9. A 20-newton force is pushing two blocks horizontally along a frictionless floor as show below. What is the force that the 8-kilogram mass exerts on the 2-kilogram mass?(A) 6 N(B) 8 N(C) 16 N(D) 2 N(E)
9、24 N10. A 30 kg mass is resting on a rough, horizontal surface. A horizontal force of 100 N is required just to start it moving. What is the approximate value for the coefficient of static friction? (A) 0.5(B) 0.4(C) 0.3(D) 0.2(E) 0.1(Questions 11-17 are AP level)11. A person standing on a horizonta
10、l floor feels two forces: the downward pull of gravity and the upward supporting force from the floor. These two forces?(A) have equal magnitudes and form an action / reaction pair (B) have equal magnitudes but do not form an action / reaction pair(C) have unequal magnitudes and form an action / rea
11、ction pair(D) have unequal magnitudes and do not form an action / reaction pair(E) None of the above12. A person who weights 800N steps onto a scale that is on the floor of an elevator car. If the elevator accelerates upward at a rate of 5 m/s2, what will the scale read?(A) 400 N(B) 800 N(C) 1000 N(
12、D) 1200 N(E) 1600 N13. A frictionless inclined plane of length 20m has a maximum vertical height of 5m. If an objuect of mass 2kg is placed on the plane, which of the following best approximates the net force it feels?(A) 5 N(B) 10 N(C) 15 N(D) 20 N(E) 30 N14. A 20 N block is being pushed across a h
13、orizontal table by an 18 N force. If the coefficient of kinetic friction between the block and the table is 0.4, find the acceleration of the block(A) 0.5 m/s2(B) 1 m/s2(C) 5 m/s2(D) 7.5 m/s2(E) 9 m/s215. The coefficient of static friction between a box and a ramp is 0.5. The ramps incline angle is
14、30. If the box is placed at rest on the ramp, the box will(A) accelerate down the ramp(B) accelerate briefly down the ramp but then slow down and stop(C) move with constant velocity down the ramp(D) not move(E) Cannot be determined from the information givenSection 2: Free Response16. In the diagram
15、 below, a massless string connects two blocksof mass m1 and m2 , respectivelyon a flat, frictionless tabletop. A force F pulls on Block 2, as shown: Solve for the following in terms of given quantities:(A) Draw and label all of the forces acting on Block 1 (B) Draw and label all of the forces acting
16、 on Block 2(C) What is the acceleration of Block 1(D) What is the tension in the string connecting the two blocks?17. A sky diver is falling with speed v0 through the air. At that moment (time t=0), she opens her parachute and experiences the force of air resistance whose strength is given by the eq
17、uation F=kv, where k is a proportionality constant and v is her descent speed. The total mass of the sky diver and equipment is m. Assume that g is constant throughout her descent.(A) Draw and label all of the forces acting on the sky diver after her parachute opens(B) Determine the sky divers accel
18、eration in terms of m, v, k, and g(C) Determine the sky divers terminal speed ( that is, the eventual constant speed of descent. )(D) Sketch a graph of v as a function of time, starting at t=0 and going until she lands, being sure to label important values on the vertical axis.Answer SheetClass:_ Na
19、me:_ Score:_Section 1: Multiple Choices-1 (A) (B) (C) (D) (E)2 (A) (B) (C) (D) (E)3 (A) (B) (C) (D) (E)4 (A) (B) (C) (D) (E)5 (A) (B) (C) (D) (E)6 (A) (B) (C) (D) (E)7 (A) (B) (C) (D) (E)8 (A) (B) (C) (D) (E)9 (A) (B) (C) (D) (E)10 (A) (B) (C) (D) (E)11 (A) (B) (C) (D) (E)12 (A) (B) (C) (D) (E)13 (A) (B) (C) (D) (E)14 (A) (B) (C) (D) (E)15 (A) (B) (C) (D) (E)Section 2: Free Response16.17.