今日头条2017秋招编程题汇总.pdf

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1、20173a,b,c3a=b=cb-a=10c-b=10nn13mnA1,A2,.AnAn(n-1)/2mnm, 1nn,mn=11, m=4, 1, 10, 11, 2, 3, 4, 5, 6, 7, 8, 9, 42. n=200, m=25, 1 10 100 101 102 103 104 105 106 107 108 109 11 110 111 112 113 114 115 116 117 118 119 12 120 121 122 123 124 125 126 127 128 129 13 130 131 132 133 134 135 136 137 138 139 1

2、4 140 141 142 143 144 145 146 147 148 149 15 150 151 152 153 154 155 156 157 158 159 16 160 161 162 163 164 165 166 167 168 169 17 170 171 172 173 174 175 176 177 178 179 18 180 181 182 183 184 185 186 187 188 189 19 190 191 192 193 194 195 196 197 198 199 2 20 200 21 22 23 24 25 26 27 28 29 3 30 31

3、 32 33 34 35 36 37 38 39 4 40 41 42 43 44 45 46 47 48 49 5 50 51 52 53 54 55 56 57 58 59 6 60 61 62 63 64 65 66 67 68 69 7 70 71 72 73 74 75 76 77 78 79 8 80 81 82 83 84 85 86 87 88 89 9 90 91 92 93 94 95 96 97 98 99 2512080 81 82 83 84 85 86 87 88 89 9 90 91 92 93 94 95 96 97 98 99 f(x)AA0f(0)Ai-1

4、!= Ai != Ai+101.2.-1 -1 n n101 3 1 2 5 4 3 1 9 102 7100%1 =n =10, 000, 000Ai100%1 =n =10, 000, 000Paragraph N i LiWi( )( ) M N MN+M N M M 6 3An algorithm is an effective method that can be expressed within a finite amount of space and timeStarting from an initial state and initial input the instruct

5、ions describe a computationThat when executed proceeds through a finite number of successive statesEventually producing output and terminating at a final ending stateThe transition from one state to the next is not necessarily deterministicSome algorithms known as randomized algorithms incorporate r

6、andom inputNext to the transitionWormhole, infinite time and spaceThe transition from one state to the next is not necessarily deterministicN+MAn algorithm is an effective method that can be expressed within a finite amount of space The transition from one state to the next is not necessarily determ

7、inisticAn algorithm is an effective method that can be expressed within a finite amount of space and timeThe transition from one state to the next is not necessarily deterministic0 Li 5120 Wi 3230%0 N 300 M 30100%0 N 5000 M 800+-+ |+-+|+-+| | |+-+|+-+|+-+ +-+ | | | | +-+ +-+ | | |+-+ +-+ | | |+-+ +-

8、+ | | |+-+ 30%1 100%= 6100%= xBi = y i n q A n B n q x y3 23 2 46 5 81 14 83 1 30%1 = n, q = 100100%1 = n, q, Ai, Bi = 10530%100%1 = n, q = 1001 = n, q, Ai, Bi = 1051 = n, q, Ai, Bi = 105(int)m na1 a2 amb1 b2 bn5 411 15 9 12 31 8 3 73 30%, 0 m 30, 0 n 30100%0 m 100000, 0 n 100000m,n0 m 30, 0 n 300 m

9、 100000, 0 n 100000m,n0 m 30, 0 n 300 m 100000, 0 n 1000000 m 100000, 0 n 100000DAU(DAU) N M (uid)uid 0 N+1uid M129331111115922069433592201111110 4 0 uid 263 1s, 32MB30%0 N 100,000, 0 M 100,000100%0 N 1,000,000, 0 M 800,0000 uid 263 1s,30%100%N 100,000, 0 M 100,0000 N 1,000,000, 0 M 800,000N 100,000

10、, 0 M 100,000N 1,000,000, 0 M 800,000* * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * *1 2 3 4 5 6 7 8 9 0* * * * * * * * * * * *+ - * = 110 + 311* * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * 22 5 2* * * * * * * * * * * * * * * * * * * * * * * * * * * 20%100%10000100%80%* * * * * * * * 2 * *