C课程设计俄罗斯方块(共41页).doc

上传人:飞****2 文档编号:14480690 上传时间:2022-05-04 格式:DOC 页数:41 大小:856KB
返回 下载 相关 举报
C课程设计俄罗斯方块(共41页).doc_第1页
第1页 / 共41页
C课程设计俄罗斯方块(共41页).doc_第2页
第2页 / 共41页
点击查看更多>>
资源描述

《C课程设计俄罗斯方块(共41页).doc》由会员分享,可在线阅读,更多相关《C课程设计俄罗斯方块(共41页).doc(41页珍藏版)》请在得力文库 - 分享文档赚钱的网站上搜索。

1、精选优质文档-倾情为你奉上C课程设计俄罗斯方块专心-专注-专业C#程序设计实训报告题目:俄罗斯方块 专 业_计算机科学与技术 _年级班别_ 计算机09-2班_ 学 号 学生姓名_ _指导教师_ 成 绩 年 1 月 目 录3.5使用说明界面.8一、系统设计要求1.1 课题分析本游戏系统是利用C#实现的, 是制作为我们所熟悉的非常简单的俄罗斯方块游戏,该系统能实现的具体功能如下:1) 能简便的开始游戏,游戏中的方块的功能与日常我们所熟悉的游戏的功能一致,各种块的设置也一致,包括方块的旋转,加速下降,左右移动,满行消去,满行消去自动加分,以及到顶游戏结束等功能;2) 能够经过对话框窗体说明各个功能的

2、使用说明,以及一些其它功能。3) 界面简洁美观,简单易用。跟其它一般的游戏相差不大。1.2 设计环境本程序选择Visual Studio 作为实验环境。1.3 设计思路用面向对象的方法分析系统对于俄罗斯方块的程序制作,我们能够定义一个或者几个类,专门来描述俄罗斯方块,在这个类中,包含与之相关的方法、属性和字段,经过封装,实现其业务逻辑。其中,每一个俄罗斯方块都有相同的特征,由4个小正方形构成,有旋转,左右移动,下落的动作,整行被填满除去并计算分数而构成行的小正方体块。基中块的形状类型有7种:田、一、L、倒L、Z、倒Z、上。在窗口中经过调用主窗体Form1当中的菜单栏来设置游戏的开始、暂停、结束

3、、重新开始以及推出程序。还能够经过其菜单中游戏说明选项来查看游戏各个键的使用说明,还可调用帮助菜单来查看版权说明。二、课题总体框架设计 2.1、 程序流程图开始窗口初始化读取游戏开始游戏开启游戏时钟随机形成方块判断是否可移旋转左移右移加速下降暂停结束绘制方块是否越顶是否满行消行结束加分2.2、 类的结构图三、课题实现3.1程序主界面3.2 开始游戏界面3.3游戏结束3.4暂停游戏3.5使用说明界面和版权界面3.6关键程序代码1、Form1类1) 构造函数,设定当前运行的方块,下一个即将出现的方块,方块产生的位置,玩家积分,游戏开关等。public partial class Form1 : F

4、orm private Block currentBlock; /当前在运行的方块private Block nextBlock; /下一个即将出现的方块private Point startLocation = new Point(bianjie.SingleSquareSize * 8, 0); /方块产生的位置private int score = 0; /玩家积分private bool stillRuning = false; /游戏运行开关2) 键盘操作:用来选择方块的移动方向,是向右移动,向左移动,向下加速,旋转,还是暂停。/*键盘操作*/private void Form1_K

5、eyDown(object sender, KeyEventArgs e) switch (e.KeyCode) case Keys.Right: currentBlock.right() ; break;/向右移动 case Keys.Left: currentBlock.left() ; break; /向左移动 case Keys.Up: currentBlock.Rotate(); break; /旋转 case Keys.Down: while (currentBlock.down() ; break; /向下加速 case Keys.Space: /空格:暂停 timer1.Ena

6、bled = !timer1.Enabled; if (!timer1.Enabled) showMsg(暂 停); else msg.SendToBack(); break; picBack.Focus(); 3) 时钟触发处理函数,使方块自动的向下移动,每1秒使方块向下移动一次 /*游戏时钟*/ private void timer1_Tick(object sender, EventArgs e) if (!stillRuning) return; /检测是否还能够下移 if (!currentBlock.down() if (currentBlock.Top() = 0) /如果到顶则

7、游戏结束 showMsg(Game Over!); stillRuning = false; timer1.Stop(); return; /否则计算分数并继续 int eraseLines = bianjie.CheckLines(); if (eraseLines 0) score += bianjie.width * eraseLines; t_score.Text = score.ToString(); picBack.Invalidate(); Application.DoEvents(); bianjie.Redraw(); /产生下一个block currentBlock = n

8、ew Block(startLocation, nextBlock.blockType); currentBlock.Draw(bianjie.winHandle); pic_preView.Refresh();nextBlock = new Block(new Point(50, 50), Block.BlockTypes.undefined); nextBlock.Draw(pic_preView.Handle); currentBlock.down(); 4) 对窗口进行重绘 /*窗口重绘*/ private void Form1_Activated(object sender, Eve

9、ntArgs e) picBack.Invalidate(); Application.DoEvents(); bianjie.Redraw(); 2、SingleBlock类1) 构造单个方块的尺寸,颜色,前景色,背景色public SingleBlock(Size initSize,Color initForeColor,Color initBackColor) size = initSize; foreColor = initForeColor; backColor = initBackColor; 2) 画方块,用GDI+绘画,画出填充正方形 /画方块 public void Draw

10、(System.IntPtr winHandle) Graphics g = Graphics.FromHwnd(winHandle); GraphicsPath gp = new GraphicsPath(); Rectangle rect = new Rectangle(location, size); gp.AddRectangle(rect); Color surroundColor = new Color backColor ; PathGradientBrush pgb = new PathGradientBrush(gp); pgb.CenterColor = foreColor

11、; pgb.SurroundColors = surroundColor; g.FillPath(pgb, gp); /擦除方块 public void Erase(System.IntPtr winHandle) Graphics g = Graphics.FromHwnd(winHandle); Rectangle rect = new Rectangle(location,size); g.FillRectangle(new SolidBrush(bianjie.BackColor),rect); 3、Block类1)随机产生方块形状,并设置四个方块的颜色public Block(Poi

12、nt thisLocation,BlockTypes bType) /当blockType为undefined时,随机产生方块形状 Random rand=new Random(); if (bType = BlockTypes.undefined) blockType = (BlockTypes)(rand.Next(7) + 1); else blockType = bType; /设置四小方块的颜色 int i=(int)blockType-1; foreColor = bianjie.BlockForeColori; backColor = bianjie.BlockBackColor

13、i; Size SingleSquareS=new Size(SingleSquareSize,SingleSquareSize); SingleSquare1 = new SingleBlock(SingleSquareS, foreColor, backColor); SingleSquare2 = new SingleBlock(SingleSquareS, foreColor, backColor); SingleSquare3 = new SingleBlock(SingleSquareS, foreColor, backColor); SingleSquare4 = new Sin

14、gleBlock(SingleSquareS, foreColor, backColor);2)设置小方块的位置,组合成指定形状的方块 /设置小方块的位置,组合成指定形状的一个大方块 switch (blockType) case BlockTypes.SingleSquare: /组合成正方形 SingleSquare1.location = new Point(thisLocation.X, thisLocation.Y); SingleSquare2.location = new Point(thisLocation.X + SingleSquareSize, thisLocation.

15、Y); SingleSquare3.location = new Point(thisLocation.X,thisLocation.Y+SingleSquareSize);SingleSquare4.location = new Point(thisLocation.X+SingleSquareSize,thisLocation.Y+SingleSquareSize); break;case BlockTypes.line: /组合成线形 SingleSquare1.location = new Point(thisLocation.X, thisLocation.Y); SingleSqu

16、are2.location = new Point(thisLocation.X + SingleSquareSize, thisLocation.Y); SingleSquare3.location = new Point(thisLocation.X + 2 * SingleSquareSize, thisLocation.Y); SingleSquare4.location = new Point(thisLocation.X + 3 * SingleSquareSize, thisLocation.Y); break; case BlockTypes.J: /组合成J形 SingleS

17、quare1.location = new Point(thisLocation.X + SingleSquareSize, thisLocation.Y); SingleSquare2.location = new Point(thisLocation.X + SingleSquareSize, thisLocation.Y + SingleSquareSize); SingleSquare3.location = new Point(thisLocation.X + SingleSquareSize, thisLocation.Y + 2 * SingleSquareSize); Sing

18、leSquare4.location = new Point(thisLocation.X, thisLocation.Y + 2 * SingleSquareSize); break; case BlockTypes.L: /组合成l形 SingleSquare1.location = new Point(thisLocation.X, thisLocation.Y); SingleSquare2.location = new Point(thisLocation.X, thisLocation.Y + SingleSquareSize); SingleSquare3.location =

19、new Point(thisLocation.X, thisLocation.Y + 2 * SingleSquareSize); SingleSquare4.location = new Point(thisLocation.X + SingleSquareSize, thisLocation.Y + 2 * SingleSquareSize); break; case BlockTypes.T: /组合成T形 SingleSquare1.location = new Point(thisLocation.X, thisLocation.Y); SingleSquare2.location

20、= new Point(thisLocation.X + SingleSquareSize, thisLocation.Y); SingleSquare3.location = new Point(thisLocation.X + 2*SingleSquareSize, thisLocation.Y); SingleSquare4.location = new Point(thisLocation.X + SingleSquareSize, thisLocation.Y +SingleSquareSize); break; case BlockTypes.Z: /组合成z形 SingleSqu

21、are1.location = new Point(thisLocation.X, thisLocation.Y); SingleSquare2.location = new Point(thisLocation.X + SingleSquareSize, thisLocation.Y); SingleSquare3.location = new Point(thisLocation.X + SingleSquareSize, thisLocation.Y + SingleSquareSize); SingleSquare4.location = new Point(thisLocation.

22、X + 2*SingleSquareSize, thisLocation.Y + SingleSquareSize); break;case BlockTypes.S: /组合成S形 SingleSquare1.location = new Point(thisLocation.X, thisLocation.Y + SingleSquareSize); SingleSquare2.location = new Point(thisLocation.X + SingleSquareSize, thisLocation.Y + SingleSquareSize); SingleSquare3.l

23、ocation = new Point(thisLocation.X + SingleSquareSize, thisLocation.Y); SingleSquare4.location = new Point(thisLocation.X + 2 * SingleSquareSize, thisLocation.Y); break; /*画方块*/ public void Draw(System.IntPtr winHandle) SingleSquare1.Draw(winHandle); SingleSquare2.Draw(winHandle); SingleSquare3.Draw

24、(winHandle); SingleSquare4.Draw(winHandle); /*擦方块*/ public void Erase(System.IntPtr winHandle) SingleSquare1.Erase(winHandle); SingleSquare2.Erase(winHandle); SingleSquare3.Erase(winHandle); SingleSquare4.Erase(winHandle); 3) 移动方块 /*移动*/ public bool down() /检测是否能够下移 if (bianjie.isEmpty(SingleSquare1

25、.location.X / SingleSquareSize, SingleSquare1.location.Y / SingleSquareSize + 1) & bianjie.isEmpty(SingleSquare2.location.X / SingleSquareSize, SingleSquare2.location.Y / SingleSquareSize + 1) &bianjie.isEmpty(SingleSquare3.location.X / SingleSquareSize, SingleSquare3.location.Y / SingleSquareSize +

26、 1) &bianjie.isEmpty(SingleSquare4.location.X / SingleSquareSize, SingleSquare4.location.Y / SingleSquareSize + 1) Erase(bianjie.winHandle); SingleSquare1.location = new Point(SingleSquare1.location.X, SingleSquare1.location.Y + SingleSquareSize); SingleSquare2.location = new Point(SingleSquare2.loc

27、ation.X, SingleSquare2.location.Y + SingleSquareSize);SingleSquare3.location = new Point(SingleSquare3.location.X, SingleSquare3.location.Y + SingleSquareSize); SingleSquare4.location = new Point(SingleSquare4.location.X, SingleSquare4.location.Y + SingleSquareSize); Draw(bianjie.winHandle); return

28、true; else /如果不能下移了 bianjie.stopSingleSquare(SingleSquare1, SingleSquare1.location.X / SingleSquareSize, SingleSquare1.location.Y / SingleSquareSize);bianjie.stopSingleSquare(SingleSquare2, SingleSquare2.location.X / SingleSquareSize, SingleSquare2.location.Y / SingleSquareSize); bianjie.stopSingleS

29、quare(SingleSquare3, SingleSquare3.location.X / SingleSquareSize, SingleSquare3.location.Y / SingleSquareSize); bianjie.stopSingleSquare(SingleSquare4, SingleSquare4.location.X / SingleSquareSize, SingleSquare4.location.Y / SingleSquareSize); return false; /表示能够弹出下一个block了 public bool left() /检测是否能够

30、左移 if (bianjie.isEmpty(SingleSquare1.location.X / SingleSquareSize-1, SingleSquare1.location.Y / SingleSquareSize) &bianjie.isEmpty(SingleSquare2.location.X / SingleSquareSize-1, SingleSquare2.location.Y / SingleSquareSize) &bianjie.isEmpty(SingleSquare3.location.X / SingleSquareSize-1, SingleSquare

31、3.location.Y / SingleSquareSize) & bianjie.isEmpty(SingleSquare4.location.X / SingleSquareSize-1, SingleSquare4.location.Y / SingleSquareSize) Erase(bianjie.winHandle); SingleSquare1.location = new Point(SingleSquare1.location.X - SingleSquareSize, SingleSquare1.location.Y); SingleSquare2.location =

32、 new Point(SingleSquare2.location.X - SingleSquareSize, SingleSquare2.location.Y); SingleSquare3.location = new Point(SingleSquare3.location.X - SingleSquareSize, SingleSquare3.location.Y); SingleSquare4.location = new Point(SingleSquare4.location.X - SingleSquareSize, SingleSquare4.location.Y); Dra

33、w(bianjie.winHandle); return true; else /如果不能左移了 return false; public bool right() /检测是否能够右移 if (bianjie.isEmpty(SingleSquare1.location.X / SingleSquareSize +1, SingleSquare1.location.Y / SingleSquareSize) &bianjie.isEmpty(SingleSquare2.location.X / SingleSquareSize +1, SingleSquare2.location.Y / Si

34、ngleSquareSize) &bianjie.isEmpty(SingleSquare3.location.X / SingleSquareSize +1, SingleSquare3.location.Y / SingleSquareSize) &bianjie.isEmpty(SingleSquare4.location.X / SingleSquareSize +1, SingleSquare4.location.Y / SingleSquareSize) Erase(bianjie.winHandle); SingleSquare1.location = new Point(Sin

35、gleSquare1.location.X + SingleSquareSize, SingleSquare1.location.Y ); SingleSquare2.location = new Point(SingleSquare2.location.X + SingleSquareSize, SingleSquare2.location.Y); SingleSquare3.location = new Point(SingleSquare3.location.X + SingleSquareSize, SingleSquare3.location.Y); SingleSquare4.lo

36、cation = new Point(SingleSquare4.location.X + SingleSquareSize, SingleSquare4.location.Y); Draw(bianjie.winHandle); return true; else /如果不能右移了 return false; 4) 旋转方块/*旋转block*/public void Rotate() /保存每个小块的位置 Point oldPosition1 = SingleSquare1.location; Point oldPosition2 = SingleSquare2.location; Poi

37、nt oldPosition3 = SingleSquare3.location; Point oldPosition4 = SingleSquare4.location; /保存当前的方向 RotateDirections oldRotation = myRotation; /开始试着旋转方块,旋转方向:顺时针方向 旋转中心点为形状拐点 Erase(bianjie.winHandle); switch(blockType) case BlockTypes.SingleSquare: break; case BlockTypes.line: /直线的旋转只有两种方向 switch (myRot

38、ation) case RotateDirections.North: myRotation = RotateDirections.East; SingleSquare1.location = new Point(SingleSquare2.location.X-SingleSquareSize,SingleSquare2.location.Y); SingleSquare3.location = new Point(SingleSquare2.location.X+SingleSquareSize,SingleSquare2.location.Y); SingleSquare4.locati

39、on = new Point(SingleSquare2.location.X + 2 * SingleSquareSize, SingleSquare2.location.Y); break; case RotateDirections.East: myRotation = RotateDirections.North; SingleSquare1.location = new Point(SingleSquare2.location.X,SingleSquare2.location.Y-SingleSquareSize); SingleSquare3.location = new Point(SingleSquare2.location.X, SingleSquare2.location.Y +SingleSquareSize); SingleSquare4.location = new Point(SingleSquare2.location.X, SingleSquare2.location.Y + 2 *

展开阅读全文
相关资源
相关搜索

当前位置:首页 > 教育专区 > 教案示例

本站为文档C TO C交易模式,本站只提供存储空间、用户上传的文档直接被用户下载,本站只是中间服务平台,本站所有文档下载所得的收益归上传人(含作者)所有。本站仅对用户上传内容的表现方式做保护处理,对上载内容本身不做任何修改或编辑。若文档所含内容侵犯了您的版权或隐私,请立即通知得利文库网,我们立即给予删除!客服QQ:136780468 微信:18945177775 电话:18904686070

工信部备案号:黑ICP备15003705号-8 |  经营许可证:黑B2-20190332号 |   黑公网安备:91230400333293403D

© 2020-2023 www.deliwenku.com 得利文库. All Rights Reserved 黑龙江转换宝科技有限公司 

黑龙江省互联网违法和不良信息举报
举报电话:0468-3380021 邮箱:hgswwxb@163.com